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integrate
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\[\int\limits_{?}^{?} sinxcos^2x dx\]
\[u=\cos(x)\]
wont there still be an x though?
\[\large\rm \int\limits \sin x (\cos x)^2~dx\]An x where?
\[\cos ^{2}x=\frac{ 1+\cos2x }{ 2 }\]
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If you make that substitution, what do you get for your differential?\[\large\rm u=\cos x\]\[\large\rm du=?\]
-sinx
Yes\[\large\rm du=-\sin x~dx\]
Do you see how that helps? If not I can color code it.
OHH
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Oh, now i understand where @zepdrix was going. Use their method.
Sorry i'm not thinking xD Okay thank you for the help!!
Half Angle Identity was a clever idea royal :D I think the sine gets in the way though.
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