Question

Limit question?

Answer 1

\[\lim \frac{ 3 }{ 1+2e^x }\]

Answer 2

As x approaches negative infinity

Answer 3

apply the limit property to both numerator and the denominator
on the top constant remains constant
and in the bottom u get infinity
3 over infinity is zero

Answer 4

My answer book is saying 0 is incorrect... that's the answer I got as well

Answer 5

give me a second i will solve it

Answer 6

Okay thank you

Answer 7

OK sorry i missed the negative infinity part,
SO the answer should be 3
if u want i can post it

Answer 8

How do you get 3? What do you do for the 2e^x part?

Answer 9

\[\lim_{x\to -\infty} \frac{ 3 }{ 1+2e^x }\]

Answer 10

\[\lim_{x\to -\infty}e^x=0\] example \(e^{-10000}\) is \(\frac{1}{e^{10000}}\)

Answer 11

\[\frac{ \lim_{x \rightarrow -\infty } 3}{ \lim_{x \rightarrow - \infty} 1+ 2e ^{x} }\]
now i will sub in for infinity :
\[\frac{ 3 }{ 1+ 2e ^{-\infty } }\]
\[\frac{ 3 }{ 1+ 2e ^{\frac{ 1 }{ \infty } } }\]
\[\frac{ 3 }{ 1 + 2(\frac{ 1 }{ \infty }) }\]
\[\frac{ 3 }{ 1+ 2(0) }\]
\[\frac{ 3 }{ 1 + 0 }\]
\[\frac{ 3 }{ 1 } = 3\]

Answer 12

Thank you so much!! That clears things up. Does any constant raised to negative infinity equal zero?

Answer 13

yes because u will change it into a fraction