What is the value of the discriminant in the equation shown below? x^2-6x+4=0
Compare your equation to ax^2 + bx + c = 0. What are the values of a, b and c? a=? b=? c=?
a=x^2 b=-6x c=4
a, b and c are called "coefficients." Focus on the 1 in 1x^2, the -6 in -6x, and the 4. a=1 b=-6 c=4. Again, do not include the powers of x: x^2, x, x^0. Now, what is the value of b^2?
36
That's right: (-6)^2=36. What is the value of a*c? (a times c)
4
Good! Now please write out "b^2 - 4ac," using your previous calculations. b^2-4ac= ?
36-16=20
You're doing great. That 's the "discriminant" of the given equation. You're done. When told to find the "discriminant," calculate b^2-4ac.
oh ok
so 20 is the answer
Were you to continue, to find the two roots of the given equation, you'd evaluate\[x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]
Yes, the discriminant here is 20, and you're done. But be sure you understand that b^2-4ac is part of the quadratic formula, given above, by which we find the "roots" or "zeros" of the given quadratic equation.
Thank you so much for the explanation
Best to know what you can do with a result such as your discriminant, '20.' You're welcome!
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