Question

calculus help

Answer 1

@mathmale a lot of my questions are harder to upload because i can no longer upload files or pictures ugh:-(

Answer 2

What sort of questions are they? We could talk later about how you might share illustrations of the problems you're working on.

Could you find one question that would not be hard to describe in words alone?

Answer 3

sorry i really need help now i will upload one

Answer 4

Glad to be of help and glad that our relationship is improving. I have to be firm, however: I need 100% of your attention to continue. I'd normally be going to bed at this hour.

Answer 5

im so sorry! and yes, i really appreciate your help

Answer 6

Differentiate y equals the quotient of the quantity 1 plus sine x and the quantity 1 minus cosine x.

–1
–2csc(x)sec(x)
2csc(x)sec(x)
the quotient of negative 1 times sine x plus cosine x minus 1 and the square of the quantity 1 minus cosine x

Answer 7

i can use the equation thing but i think it will take a lot longer, if we can work from this that'd be best

Answer 8

Differentiate y equals the quotient of the quantity 1 plus sine x and the quantity 1 minus cosine x.
1 + sin x
Differentiate: f(x) =

Answer 9

yes sir

Answer 10

The derivative of (f/g)(x) is

g(x) * f '(x) - f(x) * g '(x)

Answer 11

ah im seeing

Answer 12

Now, looking back to your original problem, let the numerator, f(x), be 1 + sin x
and the denominator be g(x), 1 -cos x.

Let's find the derivatives of f and g alone first, as we will need them soon.

f(x) = 1 + sin x what is the derivative, f '(x)?

g(x) = 1 - cos x. What is the derivative, g '(x)?

Answer 13

so the derivative for f'(x) is-> 1 + sin x

the derivative for f'(x) -> sin (x)

Answer 14

We need to back up a bit.

f(x) = 1 + sin x. Since the deriv. of 1 is 0 and the deriv of sin x is cos x, the overall derivative f '(x) is cos x. You OK with that?

Answer 15

ok

Answer 16

then write the overall derivative of the given fraction.

It will have this form:

g(x) * f '(x) - f(x) * g '(x)

Answer 17

hmm i believe so!

Answer 18

OK. First, a summary of our values:

f(x) = 1 + sin x
f '(x) = cos x

g(x) = 1 - cos x
g '(x) = sin x.

Agree or disagree?

Answer 19

agree!

Answer 20

Cool.

Answer 21

ok, so what next

Answer 22

so we go on our merrie way and write out the derivative of the original function following the quotient rule.

The very first quantity that shows up is g(x). So we start out with this:


(1-cos x) * ( ) - (1 + sin x) * ?

Answer 23

Which of the four quantities listed goes inside the parentheses ( ) ?

Which replaces " ? " in the equation above?

Answer 24

Hint: inside those parentheses you want the derivative of the function f(x). We already have that derivative.

Answer 25

im not sure :-( I'm sorry

Answer 26

OK. First, a summary of our values:

f(x) = 1 + sin x
f '(x) = cos x

g(x) = 1 - cos x
g '(x) = sin x.

Inside those parentheses, write "cos x," which is the same as " f '(x) "

Answer 27

Replace the question mark with g '(x), which is "sin x"

Write out the whole works now.

Answer 28

ok, well i am working it out and Im definitely ruling out answer "D"

Answer 29

I erased that because it was missing the horizonal line that indicates division.


(1-cos x) * ( ) - (1 + sin x) * ?

Answer 30

sorry it spaced out on me!!! @mathmale can we still continue help?

Answer 31

Having trouble with my connection. Not abandoning you.

Answer 32

i know sorry, i was too i had to reload one time

Answer 33

and i just read what you wrote out, makes a lot more sense to me now !

Answer 34

(1-cos x) * ( ) becomes (1-cos x) * ( cos x )

and

- (1 + sin x) * ? becomes - (1 + sin x) * sin x

Answer 35

If we multiply those out as indicated and combine terms, we get cos x - sin x - 1 (because (cos x)^2 + (sin x)^2 = 1 )

Answer 36

oh i see! I'm writing all this down, this will be so helpful in the future

Answer 37

Remember that your final result is a fraction. If we haven't made any mistakes, then that fraction would look like this:

(1-cos x) * ( cos x ) - (1 + sin x) * ( sin x)

Answer 38

ohh wow (writing this down still), i can see we are almost to the results right?

Answer 39

I have made an error or two, but we are very, very close to the correct answer.
I need to stop now, as I'm really tired.

We can follow up on this problem tomorrow to ensure that it's completely clear to you. ga

Answer 40

ok- will you be on in the morning? east coast time?

Answer 41

thank you for your help by the way, looking forward to working tomorrow!

Answer 42

I'm in southern California, so 9 am. here would be noon on the east coast.

Answer 43

Best way in which you could help yourself at this point would be to do as much as possible on all 7 of your remaining questions; i'll help with at least some of them.
Goes faster if you've already studied them and tried to solve them.

Answer 44

You're welcome! Good night.

Answer 45

ok thank you talk to you tomorrow!