Question

help please= calc!

Answer 1

Differentiate y equals the quotient of the quantity 1 plus sine x and the quantity 1 minus cosine x.

–1
–2csc(x)sec(x)
2csc(x)sec(x)
the quotient of negative 1 times sine x plus cosine x minus 1 and the square of the quantity 1 minus cosine x

Answer 2

@SkyVoltage43 @Bob @Yinshy

Answer 3

derivative of ( 1 + sinx ) / ( 1- cos x) right?

Answer 4

yep @celticcat

Answer 5

would it be C here? @celticcat

Answer 6

@JustSaiyan @Ultrilliam

Answer 7

you use the quotient rule
yes looks like

Answer 8

i did, and i got C/ can you confirm?

Answer 9

dy/dx = (1 - cos x)(cos x) - (1 + sinx) sinx / (1 - cos x)^2
= -sin x / (1 - cos x)^2

Answer 10

yes C

Answer 11

OK?

Answer 12

hold on doesnt look the same let me re check

Answer 13

let me re check that

Answer 14

can i ask another question?

Answer 15

yes i made an error on the last step it should be

- sinx + cos x - 1

Answer 16

Find the limit as h goes to 0 of the quotient of the quantity 3 times the square of the quantity x plus h, plus 7 minus the quantity 3 times x squared plus 7, and h.

6x
3x2 + h2 + 7
3x2 + 7
6x + 7

Answer 17

@celticcat i still need help with this question please

Answer 18

;-)

Answer 19

sorry:

Find the limit as h goes to 0 of the quotient of the quantity 3 times the square of the quantity x plus h, plus 7 minus the quantity 3 times x squared plus 7, and h.

6x
3x^2 + h^2 + 7
3x^2 + 7
6x + 7

Answer 20

that looks better^^^

Answer 21

what!! i just posted an answer and it disappeared!!!!
anyway C is correct

Answer 22

i know... its weird. anyways thank you! and can you help me please with the question i just asked above^^?

Answer 23

yes but i have to go for a few minutes

Answer 24

ok please hurry if you can haha:-)

Answer 25

im haveing a hard time converting the written problem I think it s limit of

3(x + h)^2 + 7 - 3x^2 + 7

Answer 26

is that right?

Answer 27

yes thats correct!

Answer 28

= 3x^3 + 6xh + h^2 - 3x^2 - 7 + 7 / h
= 6xh + h^2 / h
= 6x + h

limit as x ---> 0 = 6x

Answer 29

* that should be 3x^2 not 3x^3

Answer 30

* 3x^2 not 3x^3

Answer 31

and limit as h ---> 0

Answer 32

so the conclusion would be

Answer 33

gotta go right now

6x

Answer 34

6x? oh yeah i see! when will you be back?