Mathematics
16 Online
rootbeer003:
help
9 years ago
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satellite73:
don't you ever sleep?
9 years ago
rootbeer003:
its 7
9 years ago
satellite73:
in hawaii?
9 years ago
rootbeer003:
nope
9 years ago
satellite73:
oakland?
9 years ago
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rootbeer003:
no
9 years ago
satellite73:
ok i am out of guesses
9 years ago
satellite73:
la jolla?
fresno?
9 years ago
rootbeer003:
nnonono
9 years ago
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satellite73:
\[C=10x+15y\] yo
deschutes?
9 years ago
rootbeer003:
should i put that on the paper?
9 years ago
satellite73:
why not seems reasonable
9 years ago
satellite73:
for the next one replace x by 5, y by 3 and compute
9 years ago
rootbeer003:
..
9 years ago
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satellite73:
eugene?
9 years ago
satellite73:
eugene is in oregon doe
9 years ago
rootbeer003:
do u want my credit card number too
9 years ago
rootbeer003:
secrete security code?
9 years ago
satellite73:
why, you rich?
9 years ago
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rootbeer003:
yeas
9 years ago
rootbeer003:
OK HELP ME
9 years ago
satellite73:
ok good
credit card and also maybe routing number
9 years ago
satellite73:
i did, what more do you want?
9 years ago
rootbeer003:
like type down everything i need to know
9 years ago
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satellite73:
\[C=10x+15y\] is the first one
9 years ago
rootbeer003:
andd need to type on my hw
9 years ago
satellite73:
\[C=10\times 5+15\times 3\] for the second one
9 years ago
satellite73:
or if you want extra credit, put \[C=10\times 5+15\times 3=95\]
9 years ago
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rootbeer003:
k
9 years ago
satellite73:
this is an idiotic problem since it says define a variable for the unknown, but doesn't say what the question is
no problem we can do it anyway
9 years ago
satellite73:
put \(x=\) the number of minutes allegra went over the plan
9 years ago
satellite73:
then the equation would be \[65+0.10x=73.40\]
9 years ago
satellite73:
solve for \(x\) by subtracting \(65\) from both sides,
then divide both sides by \(0.10\)
9 years ago
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satellite73:
that is your answer to D as well, when you solve it
9 years ago
rootbeer003:
i put all those sentences?
9 years ago
satellite73:
sure although you might actually want to do the arithmetic as you write it
9 years ago
rootbeer003:
great! thanks!
9 years ago
satellite73:
ytw3
9 years ago
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satellite73:
\[65+0.10x=73.4\\
.10x=8.4\\
x=8.4\div 0.1\\
x=84\]
9 years ago
satellite73:
i do not know the formula for simple interest, because there is no such thing
do you know it?
9 years ago
rootbeer003:
I=prt or Interest=principle x rate x time
9 years ago
satellite73:
ok so \[P\times 0.4\times 3.5+P=2800\]
9 years ago
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satellite73:
i guess, really it doesn't make any sense since if the interest is really "simple" you don't get any on half a year
whatever
9 years ago
rootbeer003:
thats it?
9 years ago
satellite73:
P is the principle, r is the rate which you are told is \(4\%=.04\) and the time is \(3.5\) years
9 years ago
satellite73:
you still have to solve it i guess
9 years ago
satellite73:
first multiply \(.04\times 3.5\) use a calculator
9 years ago
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rootbeer003:
.14
9 years ago
satellite73:
ok so \[.14P+P=1.14P\] solve \[1.14P=2800\] via \[P=2800\div 1.14\]
use a calculator
9 years ago
rootbeer003:
ummm 4.0?
9 years ago
rootbeer003:
ohh
9 years ago
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rootbeer003:
2456.
9 years ago
satellite73:
yes i guess so
9 years ago
rootbeer003:
thats it?
9 years ago
satellite73:
oui
9 years ago
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rootbeer003:
does mine look normal
9 years ago
satellite73:
the answer is wrong
9 years ago
rootbeer003:
***
9 years ago
rootbeer003:
OH
9 years ago
rootbeer003:
OOPS
9 years ago
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satellite73:
looks right to me, but don't forget i don't know about simple interest, you do
9 years ago
satellite73:
yeah good luck with that
9 years ago
rootbeer003:
thanks
9 years ago
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satellite73:
you just have to do it
go to 2000 on the x axis, then put a dot up at the point (2000,1605) which will be approximate
9 years ago
satellite73:
then at 2001 go up to 1728
then at 2002 go up to 1776
then at ...
9 years ago
satellite73:
you just have to keep putting dots
there is no way around it
9 years ago
satellite73:
get rid of the first dot up at 2000 on the y
9 years ago
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satellite73:
and you got a bunch more dots to fill in, but that is what you have to do
real donkey work
9 years ago
rootbeer003:
ok next im done with this one
9 years ago
satellite73:
good
9 years ago
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satellite73:
copy and paste
9 years ago
rootbeer003:
i draw that?
9 years ago
satellite73:
yes, three horizontal line s
9 years ago
satellite73:
first one is \(y=-2\) from \(-2\) to \(-1\)
then another horizontal line on the x axis from \(-1\) to \(0\)
then another horizontal line at \(y=2\) from \(0\) to \(1\)
just like in the picture
9 years ago
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rootbeer003:
|dw:1487216975982:dw|
9 years ago
satellite73:
who said art was dead?
9 years ago
rootbeer003:
ik
9 years ago
satellite73:
yeah that will do i guess
9 years ago
rootbeer003:
can u add numbers to it?
9 years ago
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satellite73:
|dw:1487217162409:dw|
9 years ago
rootbeer003:
beautiful
9 years ago
satellite73:
like van gogh
9 years ago
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satellite73:
a) find the inverse of \[f(x)=\frac{1}{3}x+2\]
put \[y=\frac{1}{3}x+2\] then switch x and y get \[x=\frac{1}{3}y+2\] and solve for y
takes two steps, subtract 2 get \[x-2=\frac{1}{3}y\] then multiply by 3 to get \[3(x-2)=y\] or\[g(x)=3x-6\]
9 years ago
satellite73:
b) compose the functions \[f(g(x))=f(3x-6)=\frac{1}{3}(3x-6)+2=x-2+2=x\]
since you get \(x\) when you compose, they are inverses
9 years ago
satellite73:
|dw:1487217824090:dw|
9 years ago
rootbeer003:
thats all?
9 years ago
satellite73:
yes that is all
you can tell they are inverses|dw:1487217973731:dw| because they are symmetric about the line \(y=x\)
9 years ago
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rootbeer003:
alright
9 years ago
satellite73:
\[|4x-10|\geq 15\] solve \[4x-10\leq 15\] and then solve \[4x-1\ge
9 years ago
satellite73:
then solve \[4x-1\geq 15\]
9 years ago
satellite73:
first one \[4x-10\leq -14\\
4x\leq -4\\
x\leq -1\]
9 years ago
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satellite73:
second one \[4x-10\geq 14\\
4x\geq 28\\
x\geq 7\]
9 years ago
satellite73:
two intervals are \(x\leq -1\)or \(x\geq 7\)
9 years ago
rootbeer003:
um can u put those together so it makes sense
9 years ago
satellite73:
no
9 years ago
satellite73:
anyways i made a typo
9 years ago
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rootbeer003:
seriously
9 years ago
satellite73:
seriously i have to take pills and go to bed
9 years ago
satellite73:
lets try one more time
9 years ago
rootbeer003:
dont forget to put ur dentures in the container
9 years ago
satellite73:
\[|4x-10|\geq 14\]
9 years ago
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satellite73:
solve \[4x-10\leq -14\\
4x\leq -4\\
x\leq -1\]
9 years ago
satellite73:
then solve \[4x-10\geq 14\\
4x\geq 28\\
x\geq7\]
9 years ago
satellite73:
two intervals are \[x\leq -1\] OR \[x\geq 7\]
9 years ago
satellite73:
and no, there is not a way to put it together, that is what you have to do
9 years ago
rootbeer003:
its fine
9 years ago
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rootbeer003:
2 more
9 years ago
satellite73:
first graph the line \(y=\frac{3}{2}x-4\) which i can only approximate here
9 years ago
satellite73:
|dw:1487219162532:dw|
9 years ago
satellite73:
then shade the stuff below it |dw:1487219203386:dw|
9 years ago
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rootbeer003:
show ur work!
9 years ago
satellite73:
i just did
9 years ago
satellite73:
now i feel like going to by scented candles at some new age shop in a strip mall
9 years ago
satellite73:
*buy
9 years ago
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satellite73:
you have to graph those two lines
9 years ago
rootbeer003:
ill be faster if u do
9 years ago
satellite73:
\[x+y=3\] is easiest
9 years ago
satellite73:
put a point at \((0,3)\) and \((3,0)\) and connect the dots
9 years ago
satellite73:
|dw:1487219548842:dw|
9 years ago
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satellite73:
\[y=\frac{1}{4}x-2\] put a a dot at \((0,-2)\) and \((4,-1\) and connect the dots
9 years ago
satellite73:
|dw:1487219677008:dw|
9 years ago
satellite73:
your picture will be nicer because you have the grahp
9 years ago
rootbeer003:
im just using urs
9 years ago
satellite73:
then shade the region that is in both inequaties |dw:1487219820988:dw|
9 years ago