In ABCD BH | AD and BG| CD if ab= 16 bc = 12 and bh= 14, find the length of altitude BG to side CD
There should be a picture to with this question.
The symbols you posted should likely be perpendicular symbols
Ok
Okay give me a minute to take a look at this.
So there are a few things we should understand regarding this particular problem. 1. Opposite sides and angles of parallelograms are congruent. 2. Understanding that, we need to show that \(\triangle ABH \sim \triangle{CBG}\) 3. Once we have shown that, we should be in good position to find what is required.
Okay I understand
Basically, we know the triangles are similar because segments BH and AD are perpendicular. Segments BG and CD are perpendicular. Which means angles H and G are right angles.
Furthermore, angles A and C are congruent. Because of this, we know triangles AHB and CGB are similar.
Therefore, we can use the following proportion to find the length of BG: \(\dfrac{AB}{BH} = \dfrac{CB}{BG}\)
21/2 ?
Okay so BG = 10.5. But now we need to find the length of segment CD. How might we figure out the length of segment CD?
Cd=16
Very good. So what is the length of the altitude of segment BG to side CD?
10.5
Well, actually it was asking for a fraction. The length of the altitude of segment BG would the numerator and the length of side CD would be the denominator.
21/2
Not correct
Hint: \(\dfrac{BG}{CD}\)
BTW, We know 21/2 = BG. That goes in the numerator: \(\dfrac{21/2}{CD}\) You told me the length of \(\overline{CD}\) earlier so I know you know it.
What's the answer 21/32
Correct
Thank you
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