Question

Help again please

Answer 1

@psirockin3

Answer 2

@Hero

Answer 3

@Hero Please explain to me how to do this?

Answer 4

@hero are you busy?

Answer 5

@Ultrilliam get your butt on here!

Answer 6

bruh

Answer 7

Heros at work and busy he told me

Answer 8

I tagged the second best thing o.o I can try getting my bro on

Answer 9

that would be nice lol

Answer 10

A, find the average of all those.

Answer 11

(103+105+104+106+100+98+92+91+86+101)/10=evan

Answer 12

The mean? the top mean is 99.7 and the bottom is 92.5

Answer 13

wait... I mixed up my numbers
uh

Answer 14

(103+105+104+106+100+98+92+91+97+101)/10
(88+86+89+93+105+85+92+96+97+94)/10
those should get you the average... and the higher one should be the answer to A

Answer 15

I have no idea what the second one is asking.

Answer 16

and without knowing what B wants I can't solve C obviously.

Answer 17

lol

Answer 18

@PirateKing1999

Answer 19

Thanks jay

Answer 20

He doesn't know it :/ so much for being a genius e.e now i get to call him an idiot

Answer 21

lmao

Answer 22

XD, sorry panda D:

Answer 23

np

Answer 24

@pandasurvive

a) is asking about spread, which measures how varied or spread out the data is. in this scenario, an easy measure of spread is the range, which is: highest - lowest value. Simply calculate the range for Evan and Luis, then compare. Higher range = data has more spread out, lower range = data has less

b) is also asking about spread, except we only want to consider the middle 50% of the data. To find this, you will need to calculate the Quartile 1 and Quartile 3 of both data sets. Middle 50% = Quartile 3 - Quartile 1

c) is asking you to make some conclusions about the data based on what you have calculated above

I hope this helps, tag me or someone if you need additional assistance