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Suppose the test scores of students in a class are normally distributed with a mean of 92 and a standard deviation of 3. What is the z-score for a student who scored 86 on a test?
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@Vocaloid
z-score for a particular value: (that value - mean)/standard deviation
(86-92)/(3) = ?
-2. thanks
Suppose the velocities of golf swings for amateur golfers are normally distributed with a mean of 95 mph and a standard deviation of 3.9 mph. What is the difference in velocities between a golfer whose z-score is 0 and another golfer whose z-score is −1?
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work backwards using the z-score formula to find the values
(x - 95)/3.9 = 0 (y - 95)/3.9 = -1 calculate x and y
um....
(x - 95)/3.9 = 0 multiply both sides by 3.9, what do you get?
i got it actually
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ok great
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