help please
@Vocaloid
@Ultrilliam
Ima say B for self explanatory reasoning
ima say this one
I'm confused on this one actually...
@JustSaiyan
hm. the data tells us that 0.29 is very unlikely so that eliminates b and d
the question isn't written well but I would say 0.40 is plausible based on the data so A?
i guess
hint: is 3.25 on the dot plot?
that is, is there a dot at or above 3.25?
no?
good so 3.25 is outside the range of what could happen by chance, making the answer statistically significant
C?
i think thats what it is
hint: the answer IS statistically significant which answer choice matches?
A
awesome
first step: 12.1 - 8.9 = ?
3.2
good, and is 3.2 on the dot plot?
no
good, so that means it's outside the range and it is statistically significant which answer choice matches?
B
good
so how was that new job going for you?
was it being a teacher or something?
sorta yea, it's ok
nice, g4u
i have another few question i need to have help on
@Vocaloid if you can help
sure
A sample proportion of 0.62 is found. To determine the margin of error for this statistic, a simulation of 200 trials is run, each with a sample size of 100 and a point estimate of 0.62. The minimum sample proportion from the simulation is 0.73, and the maximum sample proportion from the simulation is 0.97. What is the margin of error of the population proportion using an estimate of the standard deviation? ±0.02 ±0.08 ±0.12 ±0.16
i'm not sure how to do this without using a z-table let me try finding something on the internet
find anything?
Why do you do this to me, @Ultrilliam
still looking
......
@Vocaloid you can jsut look one up on google i think
formula for error margin: +/- z * sqrt(p*(1-p)/n) the second part is easy to find since we are given p and n
sqrt(p*(1-p)/n) = 0.0485 I'm just not sure what we're supposed to use for z because the usual values aren't giving me an answer in the choices
oof, this is tricky..
there's an alternative formula that's just standard deviation/sqrt(n) the "estimate" for standard deviation is range/4 which is 0.06 but that doesn't work either since 0.06/sqrt(100) = 0.006
D?
sure, I don't have a better answer than that
The results of a survey indicate that between 76% and 84% of the season ticket holders are satisfied with their seat locations. What is the survey’s margin of error?
were you given a formula for margin of error, given range? I am not aware of such a formula existing
otherwise my best guess would just be range/2 which is just (0.84-0.76)/2 = 0.04
The results of a survey indicate that the true proportion of households who recycle paper products is likely in the interval (0.61,0.7). What is the point estimate of the proportion of households who recycle paper? Enter your answer, as a decimal
the halfway point maybe? (0.61+0.7)/2 ?
0.655
yeah that's my best guess
Based on a poll of 500 citizens, a property development group claims that 54% of the population is in favor of the construction of a new hotel near the airport. An environmental group claims that the poll is not valid and that only 38% of the citizens favor the construction of the hotel. To determine whether this sample supports the population proportion of 0.54, a simulation of 100 trials is run, each with a sample size of 200 and a point estimate of 0.38. The minimum sample proportion from the simulation is 0.32, and the maximum sample proportion from the simulation is 0.50. The margin of error of the population proportion is found using an estimate of the standard deviation. What is the interval estimate of the true population proportion? (0.42,0.66) (0.29,0.47) (0.26,0.5) (0.32,0.44)
I'm not sure what formula they want to use for this :s D seems like the only reasonable answer
maybe i should screenshot
A recent poll taken by the national ice cream industry shows that 32% of the population names vanilla as its favorite ice cream flavor. A sample of 200 people shows that only 20% of those polled names vanilla as their favorite ice cream flavor. To determine whether this sample supports the population proportion of 0.32, a simulation of 100 trials is run, each with a sample size of 50 and a point estimate of 0.20. The minimum sample proportion from the simulation is 0.16, and the maximum sample proportion from the simulation is 0.28. What is the margin of error of the population proportion using half the range? ±0.02 ±0.04 ±0.06 ±0.08
half the range is just (0.28-0.16)/2
so ±0.06 i think
alright
i got a 60%, though its alright
soz bruh
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