Question

A ball in the air has a height of h(t) + 16t^2 + 50t +3 feet after t seconds.

a. what is the average rate of change for h(t) between t=0 and t=2?

b. This means, on average, the height of the ball is (increasing or decreasing) for 0 8 years ago

Answer 1

rate of change formula

[h(2) - h(0)] / (2-0) = ?

Answer 2

sorry i dont know how to solve that

Answer 3

it's like our pizza problem

Answer 4

look at the formula

h(0) = ?

Answer 5

0?

Answer 6

h(t) + 16t^2 + 50t +3
h(0) = 16(0)^2 + 50(0) + 3 = ?

Answer 7

0=3

Answer 8

h(0) = 3, good

now find h(2)

Answer 9

167?

Answer 10

good

now find [h(2) - h(0)] / (2-0) using the values we obtained

Answer 11

82?

Answer 12

yeah that's right, 82 m/s

Answer 13

so the height is increasing

Answer 14

ok it has a drop down menu for part a: 82 (feet or seconds) per (foot or second)

Answer 15

what do i choose

Answer 16

oh right it's in feet not meters sorry

Answer 17

feet per second

Answer 18

thank you so much