Help with these two questions
@Shadow
intercept = ybar - slope*xbar where ybar and xbar are the average of the y-values and x-values respectively
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(1,1),(2,5),(3,10) Slope: 4.5 Obtain the average of all x points (1 + 2 + 3)/3 6/3 2 Obtain the average of all y points (1 + 5 + 10)/(3) 16/3 Insert the average for x and the average for y into y = mx + b, for x and y respectively. Insert the slope as well. Solve for b ( the y intercept). y = mx + b 16/3 = 4.5(2) + b 16/3 = 9 + b 16/3 = 27/3 + b b = 16/3 - 27/3 b = -11/3
Here is a link in which you can view the points and the line graphed. https://www.desmos.com/calculator/wer4qcfije
Try and see if you can solve for the second one. Just follow the steps that I showed you.
If you have any difficulty, let me know.
okay so for the slope of 1,8 and 2,7 I got -1
You do not need to solve for the slope. It is given.
For the second question, the slope is -1.5
Do you know where to start?
Yes do the average
I would do 1+2+3/3 right
Yes, to find the average for all x points. Be careful with the way you set that problem up though. if you were to copy and paste that into a computational engine, you could get 4. This is because 3/3 is 1. That is why I used the parentheses, to indicate that I am dividing the sum of those terms, by three.
It is a good habit to develop, and shows a thorough understanding of PEMDAS.
(1+2+3)/(3) = 6/3 = 2 (8+7+5)/(3) = 20/3 = 6.6
Keep it in fraction form.
so just 20/3
Yes. Now what is our next step?
y=mx+b 20/3=-1.5(2)+b 20/3=-3+b 20/3=-9/3+b b=20/3-(-9/3)
Don't know what you did in your last step, but you just have to add 9/3 to both sides.
y=mx+b 20/3=-1.5(2)+b 20/3=-3+b 20/3=-9/3+b
is this right so far?
Yes
b= 9 and 2/3
29/3??????
You had me scared for a little bit w/ b= 9 and 2/3. But yes, it is 29/3. Let me get a graph for you real quick.
sure!
Lol didn't want to scare you :S
See how the points fall evenly on each side. We are pitch perfect with our y intercept. Good job.
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