Question

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Answer 1

@Vocaloid

Answer 2

graph both equations https://www.desmos.com/ you will be able to find out the difference .

Answer 3

1 horizontal to right and reflection over x axis?

Answer 4

@Nnesha

Answer 5

@Allison

Answer 6

@AshtynThatDrummerGirl @Bearclaws72 There ;p

Answer 7

where is she?

Answer 8

@Falconmaster

Answer 9

https://s1.postimg.org/6b89sxmskf/Capture.png
@Falconmaster

Answer 10

putting a negative sign outside the function reflects across the x-axis

Answer 11

think about what |8x| looks like compared to |x|

Answer 12

stretched

Answer 13

we have to be careful with our terminology here

Answer 14

vertical

Answer 15

is the second one horizontal to right and shift down 7 units

Answer 16

since the 8 is inside the absolute value sign, it must be a horizontal stretch/shrink

Answer 17

oh ok

Answer 18

now, if we imagine taking our graph and stretching/shrinking horizontally, then |8x| is actually a compression/shrink

Answer 19

i thought it was compression when i looked at the graph

Answer 20

second one?

Answer 21

so for the very first problem it's a horizontal compression by 8 and a reflection across the x-axis

Answer 22

let's look at the second one then

Answer 23

f(x) = 3^x
g(x) = 3^(-x+7)

since we multiplied x by -1 (inside the function) this would be a horizontal reflection across y-axis

Answer 24

now, we need to be careful with the + 7. intuitively you would think it would be a shift to the right, but for horizontal transformations, the direction is actually the opposite to the sign (to the left)

Answer 25

I've actually answered a good bit need some answers checked though

Answer 26

oh

Answer 27

now let's look at 25

Answer 28

so 21 is over y axis left?

Answer 29

yes

Answer 30

https://s1.postimg.org/4hc0it6v8f/Capture.png

Answer 31

if f(x) = x^3
and g(x) = (1/2)(x-4)^3 + 5

what transformations are being done to f(x) to get g(x)?

Answer 32

one question at a time please

Answer 33

horizontal right

Answer 34

4 units

Answer 35

yes, left or right?

Answer 36

right

Answer 37

good, what else?

Answer 38

vertical up 5 units

Answer 39

good, one more

Answer 40

compression vertically

Answer 41

good, that's it

Answer 42

by 2

Answer 43

should be 1/2 I believe (could be wrong about this)

Answer 44

since the 1/2 is there that makes sense

Answer 45

i said c

Answer 46

that's not correct, try one more time

Answer 47

a?

Answer 48

which interval captures those two black regions?

Answer 49

hint: it starts at negative infinity and ends at 0

Answer 50

so it's d

Answer 51

good

Answer 52

gtg be back later

Answer 53

how long?

Answer 54

https://s1.postimg.org/5196g243sv/Capture.png

Answer 55

this one i think is c

Answer 56

it says decreasing not increasing

Answer 57

where is the function decreasing?

Answer 58

-infinity -1 the one that is going downward

Answer 59

oh it's b because it's also at 0

Answer 60

(-infinity,-1) is increasing not decreasing so it is not part of the solution

Answer 61

so a then because it is at 0

Answer 62

it's decreasing from (0,1) and (1,infinity)

yes, so A is the answer

Answer 63

yay this next question is on intercepts joy

Answer 64

https://s1.postimg.org/4lc7o5j8vj/Capture.png

Answer 65

hint: where is the graph touching the x-axis? keep in mind the graph does not reach 0 at either extremity

Answer 66

-1 ?

Answer 67

it means no intercept, yes

Answer 68

intercept

Answer 69

what about y-intercepts?

Answer 70

that's what i meant looked at next question and so the y is -1

Answer 71

b is answer

Answer 72

good that's it

Answer 73

asymptotes next question

Answer 74

https://s1.postimg.org/4ul9uft2dr/Capture.png

Answer 75

let's start with vertical

what are the vertical lines the graph approaches but does not cross?

Answer 76

-1 aren't both x and y -1 for asymptote

Answer 77

no

Answer 78

it crosses -1 slightly i'm confused

Answer 79

the graph isn't drawn well but there's an asymptote at x = -1

Answer 80

what about the other one?

Answer 81

ok that's what i thought but the you said crossed

Answer 82

is it -2 then?

Answer 83

??? where are you getting -2 from???

Answer 84

y=-2

Answer 85

we are only talking about vertical asymptotes for now

Answer 86

1

Answer 87

good, so your vertical asymptotes are -1 and 1

Answer 88

let's move on to horizontal ones

Answer 89

so horizontal is -2

Answer 90

well you said -1 wasnt right so it must be 0

Answer 91

(y = -2 is not an asymptote. I don't know how to explain this well)

Answer 92

good, y = 0

Answer 93

those are your three asymptotes

Answer 94

my teacher told me to put a line straight down the sides of the y and whatever it was closest to is the asymptote

Answer 95

I guess it's possible she would want you to mark y = -2 as an asymptote

Answer 96

https://s1.postimg.org/5cpcv08hzz/Capture.png
who knows

Answer 97

hint: is it symmetric about the y-axis?

Answer 98

yes

Answer 99

so even

Answer 100

good, is it also symmetric about y = x?

Answer 101

i'd say so

Answer 102

so neither it can't be even and odd

Answer 103

no

Answer 104

no

Answer 105

good

so it's symmetric about the y-axis but not y = x

so it is even, not odd

Answer 106

https://s1.postimg.org/7v3e8sj7lr/Capture.png

Answer 107

there's one region where the slope is 0 (a horizontal line) can you find it?

Answer 108

-infinity, -4

Answer 109

good, so A

can you close this and open a new question please

Answer 110

so if it slopes downward it's not constant

Answer 111

right, the slope must be 0