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Dang it, I don't have paper in front of me. Roses, can you do this one?
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@JustSaiyan can you help?
1. Volume of sphere =\[4/3×π×r^3\] where r=60 in this case So the volume of quarter-sphere = \[\frac{ 1 }{ 4 }×\frac{ 4 }{ 3 }×π×r^3 = \frac{ 1 }{ 3 }×\pi×60^3=226195ft^3\] to the nearest whole number
2. Since each holding tank is congruent, both of them have a radius of 30 feet, height of 110 feet Volume of a cylinder = \[\pi×r^2×h\] so volume of each half-cylinder = \[\frac{ 1 }{ 2 } ×\pi×r^2×h = \frac{ 1 }{ 2 }×\pi×30^2×110=155509ft^3\] Total volume of both cylinders =\[2×155509=311018ft^3\]
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