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Mathematics 26 Online
zarkam21:

Help please If I have a equation P=l^2R How do I rearrange this so it can be R=

zarkam21:

@Vocaloid

zarkam21:

@SourMunchkin7806

563blackghost:

\(\large\bf{P=l^{2}r}\)?

zarkam21:

Yes but it says to solve for resistance using this formula

SourMunchkin7806:

I dont know this formula...what is p, pi? and is r refering to radius

SourMunchkin7806:

oh i dont know this then im sorry

zarkam21:

The problem is what is the resistance of a lightbulb that has a power of 120 watts and a current of 0.6 amps

zarkam21:

p is power l^2 is current r is resistance

563blackghost:

Just divide by \({l^{2}}\) from both sides. \(\large\bf{r=\frac{P}{l^{2}}}\)

zarkam21:

What would the answer be then

zarkam21:

@563blackghost

zarkam21:

@Vocaloid

zarkam21:

@katherine

zarkam21:

@Vocaloid

Vocaloid:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @563blackghost Just divide by \({l^{2}}\) from both sides. \(\large\bf{r=\frac{P}{l^{2}}}\) \(\color{#0cbb34}{\text{End of Quote}}\) it's just this

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