Help please If I have a equation P=l^2R How do I rearrange this so it can be R=
@Vocaloid
@SourMunchkin7806
\(\large\bf{P=l^{2}r}\)?
Yes but it says to solve for resistance using this formula
I dont know this formula...what is p, pi? and is r refering to radius
oh i dont know this then im sorry
The problem is what is the resistance of a lightbulb that has a power of 120 watts and a current of 0.6 amps
p is power l^2 is current r is resistance
Just divide by \({l^{2}}\) from both sides. \(\large\bf{r=\frac{P}{l^{2}}}\)
What would the answer be then
@563blackghost
@Vocaloid
@katherine
@Vocaloid
\(\color{#0cbb34}{\text{Originally Posted by}}\) @563blackghost Just divide by \({l^{2}}\) from both sides. \(\large\bf{r=\frac{P}{l^{2}}}\) \(\color{#0cbb34}{\text{End of Quote}}\) it's just this
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