Help please
If I have a equation P=l^2R
How do I rearrange this so it can be R=
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zarkam21:
@Vocaloid
zarkam21:
@SourMunchkin7806
563blackghost:
\(\large\bf{P=l^{2}r}\)?
zarkam21:
Yes but it says to solve for resistance using this formula
SourMunchkin7806:
I dont know this formula...what is p, pi? and is r refering to radius
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SourMunchkin7806:
oh i dont know this then im sorry
zarkam21:
The problem is what is the resistance of a lightbulb that has a power of 120 watts and a current of 0.6 amps
zarkam21:
p is power
l^2 is current
r is resistance
563blackghost:
Just divide by \({l^{2}}\) from both sides.
\(\large\bf{r=\frac{P}{l^{2}}}\)
zarkam21:
What would the answer be then
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zarkam21:
@563blackghost
zarkam21:
@Vocaloid
zarkam21:
@katherine
zarkam21:
@Vocaloid
Vocaloid:
\(\color{#0cbb34}{\text{Originally Posted by}}\) @563blackghost
Just divide by \({l^{2}}\) from both sides.
\(\large\bf{r=\frac{P}{l^{2}}}\)
\(\color{#0cbb34}{\text{End of Quote}}\)
it's just this