Is this correct?
@Vocaloid
@563blackghost
The first one is incorrect. Since the lines are parallel that means we would keep the same slope, let's first turn this into slope intercept. \(\bf\large{2x+5y=10}\) Subract `2x` from both sides. \(\bf\large{5y=-2x+10}\) Now divide by `5`. \(\bf\large{y=-\frac{2}{5}x+2}\) So our slope is \(\bf{-\frac{2}{5}}\) which we keep and get the equation... \(\bf\large{y=-\frac{2}{5}x+b}\) We need to find `b`, so we plug in our known point `(5,-4)`. \(\large\bf{-4=-\frac{2}{5}(5)+b}\) Find `b`. What is `b`?
b=2 right?
Close it is `-2`.
So your equation is \(\bf{y=-\frac{2}{5}x-2}\)
i forgot the sign lol
XD make sure to remember it ;)
The second is close, the slope is close, but the y-intercept is wrong. Since the we want to find a perpendicular line we would find the reciprocal of the slope. So we flip the fraction and change the sign. \(\large\bf{\frac{x}{2} \rightarrow -2x}\) So our equation stands at \(\bf{y=-2x+b}\) we need to find b, so we plug in our coordinate that we want the line to go through. \(\large\bf{8=-2(1)+b}\) What is `b`?
10
Correct. So our equation is \(\bf{y=-2x+10}\).
For the third one, the answer for parallel lines is correct. REMEMBER perpendicular lines are reciprocal to the slope. `FLIP FRACTION, CHANGE SIGN`. \(\bf\large{-2x \rightarrow \frac{1}{2}x}\) So our perpendicular line would be \(\bf{y=\frac{1}{2}x+7}\). And \(\bf{y=2x-1}\) would be neither.
The fourth one is incorrect. The answer you choose could apply for perpendicular lines since the outcome of the slopes multiplied should equal `-1`. Since parallel lines have same slopes they would equal to each other. To find the slope of a line we follow by \(\large\bf{\frac{y_{2}-y_{1}}{x_{2}-x_{1}}}\). Plug. \(\Large\bf{\frac{c-a}{b}=\frac{-d}{e}}\)
thank you for checking, I am sorry but may you please check one more?
sure
\(\LARGE\bf{\checkmark}\)
nicely done!
thank you for checking :D
no problem, if you need help again just message me ^.^ that is if I am not to busy or if I am online.
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