Question

Express answer in exact form. Show all work for full credit.
A segment of a circle has a 120 arc and a chord of 8sqrt3 in. Find the area of the segment.
My answer-
To solve this we will use s=0/360 2πr where r is the radius, 0 is the angle and s is the arc length.
Using the first formula:
8√3= 120/360 x 2 x πr
24√3= 2πr
Therefore r= 12√3/π
Using the second formula:
Area of the segment= 1/2 (π0/180 - sin 0) x r²
Now plug in the values of variables:
=1/2 (3.14/120/180 - sin 120) x (12√3/π)²
=1/2 (1.2273) x 43.8152
= 26.8874 square in.
My teachers feedback-
your formulas don't make a lot of sense find the sector, the area of the triangle and the Area of Segment formulas

Answer 1

@563blackghost @Vocaloid