Rewrite the expression without using grouping symbols. 12(x-17)
Do they want it in word form?
12x-17??
Nope~
12x-17 12x-12*17 12+12*17 12x-29
@Shadow
I don't know how to do this
Distributive Property A number multiplied by a parentheses with term(s) inside will be multplied to each term within the parentheses.
What do you think the answer is?
\[12x - 204 = (12 \times x) - (12 \times 17)\]
So B
Correct
13x-29x 13(x+29) 13(x-29) x(13-29) x(29-13)
Hmm, what do you think about this one?
A?
\[13(x + 29) = (13 \times x) + (13 \times 29)\]
So yes
Oh nvm is it B
Let me illustrate a concept to you. \[(8x + 20) = 4(2x + 5) \] You can pull numbers out of a parentheses to simplify
Don't guess
I have 7 minutes left to do this, ain't nobody got time for that. D:
\[13(x-29) = (13 \times x) - (13 \times 29)\]
And we're barely on the second question.
Look at this: \[(3h + 7h) = h(3 + 7)\]
It is B
It is not
C
Yes, but I do not think you understand the rule ._.
I break rules. You're a Mod, you should know I do xD
Not thee rule, I allude to the Distributive Property
Eh.
Z/3-4z+4(z-5) when z=15 45?
\[\frac{ 15 }{ 3 } -4(15) + 4(15 -5)\] \[5 - 60 + 40 = -15\]
Oh ._.
Which shows how to use the distributive property to evaluate 6*72? 6*(70+8) 6*(70+2) 6*(70-2) 6*(70-8)
Which one makes the MOST sense?
Lmao. B.
Yes ._.
Kms.
Identify the like terms. 3q, -3p, 3pq, -11pq 3q,-3p, and 3pq -3p and 3pq 3 q and 3 pq 3pq and -11pq
Like terms means that they can be added and subtracted by each other. You cannot add terms that have a differing variable to the first. Example: 3x - 5y This cannot occur. But, 3xy - 5xy can
You would get -2xy
A?
3q - 3p + 3pq cannot occur. These are not like terms. They do not have the same variables.
C
q and pq are not the same
D
pq and pq are the same
So yes
Yes ._.
2/3a + 4/3b - 4/3a 2/3a 4/3b - 8/9a 2/3ab 4/3b - 2/3 a
This problem wants us to illustrate our knowledge of like terms. Identify for me what terms we can add
Combine like terms e.e
I'm gonna guess on it
Why ._.
Because I'm timed.
Terms with a can only add/subtract with terms with a Terms with b can only add/subtract with terms with b
\[\frac{ 2 }{ 3 }a + \frac{ 4 }{ 3 }b - \frac{ 4 }{ 3}a\] Let me rearrange it for you \[\frac{ 2 }{ 3 }a - \frac{ 4 }{ 3}a + \frac{ 4 }{ 3 }b \]
You do 2/3a - 4/3a, then leave b alone since you cannot do anything with it(no other like terms, terms with b in it)
D?
Yes
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