Ask your own question, for FREE!
Mathematics 17 Online
zarkam21:

write a function for each graph described as a transformation of y=x^2 a. y=x^2 undergoes a shift left of 2 units, then a reflection through the x-axis. b. y=x^2 undergoes a horizontal stretch by a factor of 1/3, then a shift up of 4 units.

Vocaloid:

so in the other problem we went from an equation to a description, this time we are simply going in the opposite direction

Vocaloid:

|dw:1514990047604:dw| for the first problem we will first circle the lines in the table that match the description

Vocaloid:

|dw:1514990072727:dw|

Vocaloid:

first we will replace "x" with "x+2" (be careful with parentheses) and then write a negative sign in front, outside the parentheses

zarkam21:

so f-(x+c)

zarkam21:

f-(x+2)

Vocaloid:

negative sign needs to be in front ^^ also we must use the function in the problem which is y = x^2

Vocaloid:

|dw:1514990222459:dw|

Vocaloid:

y = -(x+2)^2 = your ans see if you can try the second problem (b) using a similar line of logic

Vocaloid:

keep in mind: f(x) is what's inside the table, it's just an example of how to do it. the problem uses y = x^2 so your final answer should have y and some form of x^2 in the answer

zarkam21:

so f (ax)

zarkam21:

and f(x) +c

Vocaloid:

good, now try to replace a and c with the numbers given in the problem ^^

zarkam21:

y=1/3x^2

zarkam21:

:/

Vocaloid:

|dw:1514990512785:dw|

Vocaloid:

if (1/a) = (1/3) what is a?

zarkam21:

3

zarkam21:

SO 3X^2

Vocaloid:

good so the stretch becomes y = (3x)^2 (the 3 needs to be inside the parentheses) the transformation up by 4 just adds 4 to the outside so y = (3x)^2 + 4 = your ans

Vocaloid:

horizontal stretches and shrinks are the most confusing part of function transformations tbh

zarkam21:

Yeah that is the part that is most confusing for me, But the table does make it easier. THANKS!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!