write a function for each graph described as a transformation of y=x^2 a. y=x^2 undergoes a shift left of 2 units, then a reflection through the x-axis. b. y=x^2 undergoes a horizontal stretch by a factor of 1/3, then a shift up of 4 units.
so in the other problem we went from an equation to a description, this time we are simply going in the opposite direction
|dw:1514990047604:dw| for the first problem we will first circle the lines in the table that match the description
|dw:1514990072727:dw|
first we will replace "x" with "x+2" (be careful with parentheses) and then write a negative sign in front, outside the parentheses
so f-(x+c)
f-(x+2)
negative sign needs to be in front ^^ also we must use the function in the problem which is y = x^2
|dw:1514990222459:dw|
y = -(x+2)^2 = your ans see if you can try the second problem (b) using a similar line of logic
keep in mind: f(x) is what's inside the table, it's just an example of how to do it. the problem uses y = x^2 so your final answer should have y and some form of x^2 in the answer
so f (ax)
and f(x) +c
good, now try to replace a and c with the numbers given in the problem ^^
y=1/3x^2
:/
|dw:1514990512785:dw|
if (1/a) = (1/3) what is a?
3
SO 3X^2
good so the stretch becomes y = (3x)^2 (the 3 needs to be inside the parentheses) the transformation up by 4 just adds 4 to the outside so y = (3x)^2 + 4 = your ans
horizontal stretches and shrinks are the most confusing part of function transformations tbh
Yeah that is the part that is most confusing for me, But the table does make it easier. THANKS!
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