Vocaloid
good, that looks correct to me
this problem stinks b/c EFG isn't a triangle on the diagram but I will assume they meant EFD
Okay
ok I'm going to say that JKL and SRQ are not congruent everything else looks alright
Okay thank you, I'll post the next one
yikes I've never really learned how to do this in my own classes so I will try and find something on the internet
Okay, thank you.
so I believe the order you have posted is correct
Okay, awesome. I'll post the next one
yeah I got 18 too well done
Thank you :)
I don't think that's right, try re-applying the slope formula (y2-y1)/(x2-x1)
Okay
Perpendicular means 90 degrees right?
yes (just find the slope of the original line first, accounting for perpendicularity is easy)
Okay I'll try it
7/6 is the slope of the original line. Is that right?
good now the perpendicular slope, we just flip the num and denominator then stick a negative sign in front so -6/7 = your answer
oh really? its that easy. thank you, I'll post the next one
good
yup
yup
to get from step 5 to 6 you subtract m<3 from both sides so it would be subtraction property of equality otherwise a.o.k
I believe "open up the compass to length JK" needs to be step 2, right after drawing M everything else looks good
Okay thanks
should be "keep the compass opening + place the compass on F...etc." first choice since the original arcs must intersect the new arcs https://www.mathsisfun.com/geometry/construct-linebisect.html
Okay
the compass needs to be placed on G and then opened up all the way to H so the sides are all equal (choice C) sorry if my explanations on these construction problems are bad, I try not to give direct answers but I've never really learned these before so it's hard for me to explain ;_;
I totally get it, I don't understand most of this stuff. I don't know why but no matter how much I pay attention it just won't stick. I really appreciate all your help.
shorter side is one third the length of the longer side if the longer side is 3a then the short side is just a
|dw:1515807028537:dw|
so just (0,a) = your answer
Okay, thank you.
yup good
they're congruent, and A'B'C'D' compared to ABCD is moved to the left 7 units making answer 2 the only possibility
**** sorry answer 3
thank you, would you mind helping me with a 3 question worksheet real quick please?
sure
thank you
I am not sure how well I can explain a) but I will try ;_; since all the points are given rigid transformations, the relative y- and x- distances between corresponding points of line s and r are the same, making the slopes equal something like that ;;
Okay, let me try this.
for b) and c) you will just apply the slope formula (y2-y1)/(x2-x1) except using the variables from the points on lines r and s instead of numbers
Okay, is there any way you could walk me through b and c
|dw:1515807756342:dw|
so (y2-y1)/(x2-x1) = (k-n)/(j-m) = your answer for c) it's just the same thing, except with the two points on line s
Okay, thank you.
for d) since line q is a translation 3 units down of line s, just take the coordinates of point P' (make sure to use P' not P) and subtract 3 from the y-coordinate
okay and for c) is it (y2-y1)/(x2-x1) = (k+e-n+e)/(j-j) ?
should be j - m not j - j
also be careful with your parentheses, the numerator needs to be (k+e) - (n+e)
okay and with d) im kinda confused
so the coordinates of P' are (m,n+e) a shift of 3 units down means the y-coordinates are 3 less than they were before so just (m, n + e - 3) = your ans
Okay, thank you. I'll send the last one
this website has a diagram that explains the construction better than I can ;_; https://www.mathsisfun.com/geometry/construct-linebisect.html
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|dw:1515808613982:dw|
|dw:1515808634226:dw|
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(keep the same width)
So basically make it into a triangle?
|dw:1515808703887:dw|
then just connect the two places where the arcs intersect
|dw:1515808732767:dw|
I hope that makes sense, my brain is starting to get fried ;;
yeah, is that the finished line or is there more i need to do to it
that's it
kk last one
first find the slope of y = -3x - 8
brb
kk
-3 is the slope
good, and it wants the perpendicular line, so we take the negative reciprocal to get (1/3) as the new slope then we re-write y = (1/3)x + b then we plug in (-3,1) as our new x and y values and solve for b
awesome, thank you
b=31x+y ?
so x = -3 and y = 1 y = (1/3)x + b 1 = (1/3)(-3) + b b = ?
2?
yup so your final answer is y = (1/3)x + 2
awesome, thank you so much for all your help. hope you have a good day/night :)
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