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Mathematics 26 Online
kagekkazuto:

Last one: A mountain climber is at an altitude of 2.9 mi above the earth’s surface. From the climber’s viewpoint, what is the distance to the horizon? https://static.k12.com/nextgen_media/assets/1576280-IM3_150120_060406.jpg

563blackghost:

The segment of the horizon and the mountain climber is tangent to the circle. Meaning that the side of `3959 mi` and `x` creates a right angle. So we can find out distance as if we did Pythagorean theorem. \(\large\bf{3959^{2} +b^{2}=(3959+2.9)^{2}}\)

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