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Mathematics 19 Online
alis:

Use the probability distribution graph to answer the question. P(X≤a)=0.6 What is the value of a? Graph: https://static.k12.com/nextgen_media/assets/8078638-NG_AL2_SemA_01_UT_06.png

Vocaloid:

since P(X≤a) we need to find an X-value where the area of the curve is exactly 0.6 to the left of a

Vocaloid:

for example, if we let a = 1, the area to the left is:|dw:1520444470240:dw|

Vocaloid:

|dw:1520444504678:dw|

Vocaloid:

so we would keep testing higher and higher X-values until we find an X-value where the area to the left of that value is exactly 0.6 lmk if you get stuck or want to check your answer

alis:

ahhh ty for coming to the rescue lol i was stuck on this question all morning

alis:

wait so which value do i need to test next?

alis:

@Vocaloid

Vocaloid:

well, since 1 was way too low, try jumping up to 4 or 5

alis:

would it be 0.2*0.05?

Vocaloid:

|dw:1520445211053:dw|

Vocaloid:

if you're testing X = 4, then we'd want the area of this triangle, which is (1/2)(base)(height) = ?

alis:

4x4? times 1/2?

alis:

wait idk

Vocaloid:

|dw:1520445389143:dw|

Vocaloid:

base is 4

Vocaloid:

|dw:1520445401316:dw|

Vocaloid:

height is 0.2

Vocaloid:

area = (1/2)(0.2)*4 = 0.4, we're still a little short, try calculating the total area to the left of X = 5

Vocaloid:

|dw:1520445460891:dw|

Vocaloid:

as a hint, it's the sum of the previous triangle we calculated plus a small rectangle

Vocaloid:

|dw:1520445487177:dw|

alis:

1/2*0.25*5? that would be 0.625

Vocaloid:

keep in mind the area to the left of X = 5 is not just one triangle, it's a triangle + a rectangle

Vocaloid:

|dw:1520445590070:dw|

Vocaloid:

what's the area of this rectangle?

alis:

ehmm base = 1? i'm not sure about that and then height = 0.2 and that times 1/2 = 0.1

Vocaloid:

for a rectangle, it's just base * height, there's no 1/2

Vocaloid:

so base * height = 1 * 0.2 = 0.2 adding that to the triangle from before, 0.2 + 0.4 = 0.6, so the probability of X <= 5 is 0.6, making our value of a = 5 = your answer

alis:

ohh okay, that makes more sense than what i did. thanks again

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