Question

Please help, And Sorry to bother everyone

Answer 1

\[\frac{ 5a+37a-64 }{ 12a+36 } \div \frac{ 64a-40a^2 }{ 12a+36 }\]

Answer 2

\[\frac{ x-y }{ a+b } \div \frac{ x^2 -y^2}{ b^2-a^2 }\]

Answer 3

@Ultrilliam @563blackghost

Answer 4

Do you know what your first step might be?

Answer 5

Sorry, which expression are we doing. The first or second?

Answer 6

Well I mostly need help on the first one

Answer 7

but either way the first step would be to flip the second fraction

Answer 8

\[\frac{ 5a + 37a - 64 }{ 12a + 36 } \div \frac{ 64a - 40a^2 }{ 12a + 36 }\]

Answer 9

Is that 5a or 5a^2

Answer 10

5a^2

Answer 11

\[\frac{ 5a^2 + 37a - 64 }{ 12a + 36 } \div \frac{ 64a - 40a^2 }{ 12a + 36 }\]

Answer 12

You're correct, we do flip the second fraction. It's also called getting the reciprocal.

\[\frac{ 5a^2 + 37a - 64 }{ 12a + 36 } \times \frac{ 12a + 36 }{ 64a - 40a^2}\\]

Answer 13

\[\frac{ 5a^2 + 37a - 64 }{ 12a + 36 } \times \frac{ 12a + 36 }{ 64a -40a^2 }\]

Answer 14

Now, what do you notice about this problem that may save us some time?

Answer 15

12a + 36's cancel out

Answer 16

Correct, can you show me what it may look like after that?

Answer 17

\[\frac{ 5a^2 +3a-64}{ 64a-40a^2 }\]

Answer 18

What do you think we do after that now

Answer 19

simplify it i guess?

Answer 20

Correct, and how would you go about doing that?

Answer 21

the 5a^2 and 40a^2 can be simplified

Answer 22

In simple terms, you can't do that.

Answer 23

Yeah I looked at the factored forms of the polynomials and I didn't see a form in which could be simplified.

Answer 24

oh never mind then

Answer 25

Couldn't you just factor the numerator and denominator to simplify?
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Answer 26

@KyroKazimake We checked and couldn't find a form in which you could cancel terms out on the top and bottom. Therefore this is the most simplified form.

Answer 27

@GodSpeed Can help you with the second polynomial expression.

Answer 28

Not sure if you need the help though, since you seem to know the steps :)

Answer 29

Do you think you got it? @vaporeon246

Answer 30

Yeah i guess so Thanks @Shadow

Answer 31

No problem, we'll be here if you need us.

Answer 32

ok