Convert to vertex form. f(x)=x^2+8x+13
y=2(x-2)2+21
The 3rd 2 is supposed to be to the second
Vertex form is written in \(y=a(x-h)+k\) In which the vertex is (h,k)
Nvm XD i suck at this
To find the vertex use the equation \(\large x=\frac{-b}{2a}\)
I wouldnt know. Im in geometry lol
So it'd be \[\frac{ -8 }{ 2 }\] Which is -4
Yes so that is the x value, now substitute that into the original equation to find y \(y=(-4)^2+8(-4)+13\)
Okay so that would be y = -3?
Right that is the vertex (-4,-3)=> (h,k) So now we just substitute that into \(y=a(x-h)+k\) =>\(y=(x-(-4))-3\) or \(\boxed{y=(x+4)^2-3}\)
\(\color{#0cbb34}{\text{Originally Posted by}}\) @dude Vertex form is written in \(y=a(x-h)+k\) In which the vertex is (h,k) \(\color{#0cbb34}{\text{End of Quote}}\) Correction : \(y=a(x-h)\color{red}{^2}+k\)
Thank ye kind sir.
Join our real-time social learning platform and learn together with your friends!