Question

A???

Answer 1

good

Answer 2

3

Answer 3

keep in mind on the unit circle sin(theta) = 1/2 only occurs at two values

Answer 4

so 2

Answer 5

good

Answer 6

False

Answer 7

therefore, (1/2)sin(2 theta) = sin(theta)cos(theta)

multiplying both sides by 2 gives us

sin(2 theta) = 2sin(theta)cos(theta)

which is true making the original statement true

Answer 8

D

Answer 9

I got something slightly different, try calculating sin(pi/3 - x) based on the second identity

Answer 10

c

Answer 11

well done

Answer 12

A

Answer 13

sctually no B

Answer 14

keep in mind tan(x) = sin/cos

when you distribute the cos you get

cos^(2x) - tan(x)sin(x)cos(x) which is not cos^2(x) - tan^(x)

try rewriting the tan in terms of sin and cos and simplify the resulting expression

Answer 15

I think :/

Answer 16

cos^2(x) - tan(x)sin(x)cos(x)

cos^2(x) - sin(x)/cos(x) * sin(x) * cos(x)

the cos cancel out to get

cos^2(x) - sin^2(x)

does this equal B or C?

Answer 17

keep in mind cos^2(x) + sin^2(x) = 1 not cos^2(x) - sin^(x)

so by process of elimination it cannot be B

Answer 18

C

Answer 19

good

Answer 20

Yeah i was just gonna say that

Answer 21

I think the answer is C

Answer 22

False

Answer 23

@zarkam21

yeah, I believe it's false since they don't include the +/- sign