Find the distance between the points (2.7, 5.1) and (3, 4.7).
Same thing but with Decimals?
O, Its the Distance
Yes Distance formula =\(\sqrt{(x_2 -x_1)^2 + (y_2- y_1)^2}\)
o
Ye that's the formula.
Yeah so just substitute the points into the equation
What Points go first? I always get Confused on that...
4.7 and 5.1?
Then 3 and 2.7?
You can always start by labeling them on a piece of paper. First label the x points, then the y points. Then label the second set of points as 2, and then the first set as 1.
(2.7, 5.1) and (3, 4.7). X Y X Y
Right?
(2.7, 5.1) and (3, 4.7). Xₗ Yₗ X₂ Y₂
o
\[d = \sqrt{(3 - 2.7)^2 + (3 - 4.7)^2}\]
Right?
Where'd you get two 3's from?
...
Woops.
\[d = \sqrt{(3-2.7)^2 + (4.7-5.1)^2}\]
There?
\[d = \sqrt{(0.3)^2 + (-0.4)^2}\]
\[d = \sqrt{0.09 + (-0.16)}\]
\[d = \sqrt{-0.7}\]
... That's incorrect right @Hero?
It's not correct. Any time you square a number, you should have positive numbers afterwards.
o
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