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Jbaena1:
HELP please?! MATH
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dude:
Put f inside of g and substitute -1 \(\large =\frac{2}{2((-1)^2)+3}\)
Shadow:
\[f(x) = x^2\] \[g(x) = \frac{ 1 }{ 2x + 3}\] \[g(f(-1) = \frac{ 1 }{ 2(-1)^2 + 3}\]
Jbaena1:
Thanks everyone!
Shadow:
No problem
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