Jbaena1:

HELP please?! MATH

3 weeks ago
Jbaena1:
3 weeks ago

dude:

Put f inside of g and substitute -1 \(\large =\frac{2}{2((-1)^2)+3}\)

3 weeks ago
Shadow:

\[f(x) = x^2\] \[g(x) = \frac{ 1 }{ 2x + 3}\] \[g(f(-1) = \frac{ 1 }{ 2(-1)^2 + 3}\]

3 weeks ago
Jbaena1:

Thanks everyone!

3 weeks ago
Shadow:

No problem

3 weeks ago