Jbaena1:

HELP please?! MATH

8 months ago
Jbaena1:

1 attachment
8 months ago
dude:

Put f inside of g and substitute -1 \(\large =\frac{2}{2((-1)^2)+3}\)

8 months ago
Shadow:

\[f(x) = x^2\] \[g(x) = \frac{ 1 }{ 2x + 3}\] \[g(f(-1) = \frac{ 1 }{ 2(-1)^2 + 3}\]

8 months ago
Jbaena1:

Thanks everyone!

8 months ago
Shadow:

No problem

8 months ago
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