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Mathematics 23 Online
Sarah10:

Math

Hero:

Good evening Sarah. How far have you gotten with solving this one?

Hero:

@Sarah10 are you there?

Sarah10:

yes i am

Hero:

Great, do you know the formula for equation of a parabola given the focus and directrix?

Sarah10:

is it like (x-h)=4(y-k) something like this?

Hero:

I don't think that is correct as written. Nevertheless, that's not the formula I prefer to use. Allow me to introduce you to a formula that is more intuitive in this case.

Sarah10:

please do

Hero:

You are given two points: The focus, which is given by \((x_1, y_1) = (-2, 4)\) AND The directrix which is given by \((x_2, y_2) = (x,2)\) In this case, the equation of the parabola can be written as: \((x - x_1)^2 + (y - y_1)^2 = (x - x_2)^2 + (y - y_2)^2\) The next step would be to enter the given points to the formula and then simplify from there.

Hero:

@Sarah10 do you think you might be able to insert the given points in to the formula?

Sarah10:

yes

Hero:

Okay, would you mind typing it here using \(\LaTeX\)?

Sarah10:

for the other x do i just leave it blank?

Hero:

Allow me to color code it for you. Then you should know what to do afterwards.

Hero:

You are given two points: The focus, which is given by \((\color\red{x_1}, \color\green{y_1}) = (\color\red{-2}, \color\green{4})\) AND The directrix which is given by \((\color\orange{x_2}, \color\purple{y_2}) = (\color\orange{x},\color\purple{2})\) In this case, the equation of the parabola can be written as: \((x - \color\red{x_1})^2 + (y - \color\green{y_1})^2 = (x - \color\orange{x_2})^2 + (y - \color\purple{y_2})^2\) The next step would be to enter the given points to the formula and then simplify from there.

Sarah10:

im sorry im a bit confused here are we doing the distance formula?

Hero:

Here, allow me to demonstrate how to perform the steps since it is clear you are so deeply concerned (and a little confused) about what I am trying to show you here:

Sarah10:

very much appreciated

Hero:

Once you insert the points in to the equation of parabola you will have: \((x - \color\red{(-2)})^2 + (y - \color\green{4})^2 = (x - \color\orange{x})^2 + (y - \color\purple{2})^2\)

Hero:

Simplifying this further we will end up with: \((x + \color\red{2})^2 + (y - \color\green{4})^2 = (0)^2 + (y - \color\purple{2})^2\) or simply \((x + \color\red{2})^2 + (y - \color\green{4})^2 = (y - \color\purple{2})^2\)

Hero:

Expanding the binomial squares yield the following: \((x^2 + 4x + 4)+(y^2 - 8y + 16) = y^2 - 4y + 4\) Removing the parentheses you have: \(x^2 + 4x + 4+y^2 - 8y + 16 = y^2 - 4y + 4\)

Hero:

Notice that we can easily subtract \( y^2\) and \(4\) from both sides which will allow us to reduce the equation to just: \(x^2 + 4x - 8y + 16 = - 4y \)

Hero:

Placing like terms on the same side we have: \(x^2 + 4x + 16 = 8y - 4y\) Which easily simplifies to just: \(x^2 + 4x + 16 = 4y\)

Hero:

Notice that we can rewrite the quadratic trinomial on the left side of the equation as: \(x^2 + 4x + 4 + 12 = 4y\) And then convert it back to a binomial square: \((x + 2)^2 + 12 = 4y\)

Hero:

Lastly, we can simply divide both sides by 4: \(\dfrac{(x + 2)^2}{4} + \dfrac{12}{4} = y\) Which simplifies to \(\dfrac{(x + 2)^2}{4} + 3 = y\) And can be re-written as: \(y = \dfrac{(x + 2)^2}{4} + 3\) Which is the equation of the parabola in most simplified form.

Hero:

And to answer your question, yes the formula used to solve this question was derived from the distance formula.

Hero:

Any questions @Sarah10

Sarah10:

Thank you soooooo much! I've got to save this work for future references!! , thank you for taking your time with me

Hero:

You're most welcome.

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