Question

Jarvis needs to determine the distance across a lake. However, he can't measure this distance directly over the water. So, he set up a situation where he could use the measurements of two similar triangles to find the distance across the lake.

He selects a point X such that XZ is perpendicular to VZ, where V is a point at the other end of the lake. He then picks a point Y on XZ. From point Y, he finds point W on XV such that WY is parallel to VZ.

If XY = 3,594 feet, WY = 1,797 feet, and XZ = 10,782 feet, what is the length of VZ, the distance across the lake?

Answer 1

@hero can you tell me how to solve this

Answer 2

Okay @harliii they give you values for XY, WY, and XZ. Would you mind writing those values on the corresponding segments in the diagram please?

Answer 3

idk how to do that

Answer 4

nvm I figure it out

Answer 5

Okay great.

Answer 6

@harliii what happened to you? I only left the room for a minute because I was helping another student.

Answer 7

I figure it out I didn't know how to set it up on the drawing so I just figure it out

Answer 8

What do you mean? You don't know how to add the values for each segment to the drawing? Let me do the first one for you.

Answer 9

know like I didn't how to put it in the graph u don't have help anymore I know how to do it now

Answer 10

What do you mean you know how to do it now? If you know how to do it, post your steps.

Answer 11

xy=xz
wy=vz

Answer 12

its a fraction

Answer 13

3,594=10,782
1,797=x

Answer 14

19375254/3,594=5,391 and that is vz