Write the quadratic equation in standard form. (x - 3)^2 = 0 x^2 + 9 = 0 x^2 + 6x + 9 = 0 x^2 - 6x + 9 = 0
@Secret you were given \((x - 3)^2 = 0\) and asked to write the equation in standard form. Any ideas on how we might get started with doing so?
Multiply (x - 3) by Its self? So It would be x^2 + 9 = 0?
Ye?
Actually, that is not correct. The proper way to get started with this is to multiply the binomials. Understand that if you are given a binomial square such as \((x - a)^2\), that expression can be expanded to \((x - a)(x - a)\). From there you can use the distributive property to expand the expression then simply it until you have a quadratic expression.
simplify*
Ohhh
Oh, I see
Now what?
You re-write the equation to reflect the above information. Can you try doing that here @Secret?
(x - 3)^2 = 0 (x - 3)(x - 3) = 0 Like that??
Yes correct. Now the next step would be to actually multiply the binomials.
Would you like to try @Secret?
(x - 3)(x - 3) = 0 x^2 - 3x -3x + 6 Like this?
Question. How did you end up with 6 as the last term? Did you add or multiply to get that?
i added....was i supposed to multiply?
Yes.
Oops...then it would be this: x^2 - 3x -3x + 9 Right?
Yes, but the expression can be simplified further no?
...idk
Do you see any like terms in that expression?
or add like terms or subtract them or what
yes, there is -3x
Okay, so that means -3x can be combined with -3x.
So i should add them?
Yes, correct. Go ahead and add them
So it would be: x^2 - 6x + 9 Right?
Correct.
So which answer choice is correct?
The last one! Thx
You're most welcome. If you have any more questions, feel free to close this one and post a new question.
^-^ Ok Thank you
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