Question

For questions 5 - 6, solve for the remaining angles.

Answer 1

since we don't have any angles we have to use law of cosines

pick a side (let's use c i guess) and solve for angle C

Answer 2

c²=a²+b²-2abCos(C)

Answer 3

yup then plug in a, b, c

Answer 4

a=255
b=270
c=442.85

Answer 5

hold on a sec

Answer 6

okay

Answer 7

be careful with your labels

a = 270
b = 442.85
c = 255

Answer 8

yeah thats where i was confused

Answer 9

just remember that a is across from angle A, b is across from B, etc.

Answer 10

c²=a²+b²-2abCos(C)
225^2=270^2+442.85^2-2*270*442.85 ((Cos(C)

Answer 11

are there supposed to be 2 solutions?

Answer 12

there should only be 1

Answer 13

sometimes software can get a little confused, try solving for cos(x) then take the arcsin of the result

Answer 14

*arccos

Answer 15

0.91

Answer 16

good, then take the arccos of that to get the angle

Answer 17

24.49 degrees

Answer 18

awesome, then repeat the process for one of the other angles (A or B)

Answer 19

a²=b²+c²-2bc Cos(A)
270^2=442.85^2+225^2-2*442.85*225.2 ((Cos(A)
0.87 ----> 0.52(A)

Answer 20

make sure that your calculator/whatever is in degrees mode not radians

arccos(0.87) = 29.36 degrees

then it's just 180 - angle A - angle C = angle B to find angle B

Answer 21

180-24.49-29.36=126.15 degrees(B)

Answer 22

good, so that's 5 done, repeat the steps for triangle 6

Answer 23

A=15
B=15
C=19

Answer 24

just confirming the sides the rest i will attempt by myself

Answer 25

switch a and c

Answer 26

okay im doing it now will post it once im finished

Answer 27

is this right for C

Answer 28

c²=a²+b²-2abCos(C)
15^2=19^2+15^2-2*19*15 ((Cos(C)
arccos(19)---->208.6 degrees ©

Answer 29

cosC = 19/30 not just 19

so arccos(19/30) = ?

Answer 30

50.7

Answer 31

good, now try solving for angle A or angle B using the same method

Answer 32

a²=b²+c²-2bc Cos(A)
19^2=15^2+15^2-2*15*15 ((Cos(A)
arccos(361) =

Answer 33

is 361 right?

Answer 34

I got something a little diff

cos(A) = 89/450

A = ?

Answer 35

5

Answer 36

what is arccos(89/450) = ?

Answer 37

78.59

Answer 38

that would be for A

Answer 39

good, now we have angle A and C, just gotta solve for angle B and we're done

Answer 40

then:

180-78.59-50.7=50.71

Answer 41

and that would be angle B

Answer 42

good, that's both our triangles solved