check math questions
@Vocaloid @Hero
Let's go over the 1st one: \(\sqrt{x + 3} + 6 = 9\) First subtract 6 from both sides. Let me know what you get afterwards. Please post your steps here.
6+3=9
6+9=15
like that?
@Catherine, we're SUBTRACTING. And btw, you can use that equation button below the chat to write your equivalent equations.
omg. sorry
6-3=3 9-6=3
@Katherine, like this: \(\sqrt{x + 3} + 6 - 6 = 9 - 6\)
it gave me 72
I don't know how you get 72 from that. All we're doing is 6 - 6 = ? and 9 - 6 = ?
yaaa that's what i did earlier
I'm showing you how to subtract 6 from both sides. Let me write it out for you: |dw:1526335841604:dw| When you were doing it you kept getting numbers like "15" but then you were doing some unnecessary calculations as well. At no point is there ever a computation such as "6 - 3 = 3"
Next we have to square both sides. Are you aware of how to do that?
square both sides.. hm ok
i'm sorry, i've been on this question for 4 hrs now. and I'm all confused lol
let me try it out
when u say square both sides, which numbers do I add?
|dw:1526336363752:dw| "Squaring" does not imply addition. You might want to try reviewing the tutorials for the instruction related to this problem. \(\left(\sqrt{x + 3}\right)^2 = 3^3\)
\(\left(\sqrt{x + 3}\right)^2 = 3^2\)
it gave me 6
so, D?
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