Question

Chemical

Answer 1

that's a good guess but not quite, in a chemical reaction, there will be the same atoms on both sides of the equation, so the # of protons are actually staying the same



it has to be nuclear reactions since neither physical nor chemical rxns change the identities of the atoms invovled

Answer 2

A

Answer 3

Im actually unsure of this, could you explain to me

Answer 4

"nuclear force" indicates that we are looking for forces that act within the nucleus which excludes electrons (so not B)

neutrons don't exert any attractive or repulsive force on their own

so proton-proton repulsions are the only viable choice here

Answer 5

eins

Answer 6

C

Answer 7

tbh I feel like C+D could both work but I'm leaning more towards D because Einstein's work was in subatomic physics, C would be more along the lines of materials/applied chemistry

Answer 8

I think its either B or C

Answer 9

so there's two forces going on in the nucelus:

1. the strong force is an attractive force that holds all the protons + neutrons together
2. the electrostatic force is a repulsive force b/c all the protons repel each other

so what conditions might cause the nucleus to break apart?

Answer 10

1

Answer 11

soo if the nucleus is breaking apart would we expect: the attractive force to be weak or strong?

would we expect the repulsive force to be weak or strong?

Answer 12

remember, both forces are there, one is just weaker than the other

Answer 13

Umstrong

Answer 14

I think :/

Answer 15

Actually weak

Answer 16

so the attraction must be weak, and the repulsion must be strong, which leads us to D

Answer 17

D

Answer 18

good