Question

a hiker in Africa discovers a skull that contains 63 of its original amount of c-14. find the age of the skull to the nearest year

Answer 1

According to a formula that I found online, we have

t = [ ln (N / N0) / (-0.693) ] * 5730 where t is the age of the fossil, N / N0 is the percent of C-14 that remains and 5730 is the half-life of C-14....so we have

t = ( ln (.63) / (-0.693)) * 5730 = about 3820 yrs old

Answer 2

it says that is
not the right answer

Answer 3

N / N0 = e^(-kt)

54% = e^(-kt)

ln(.54) =-k t

[ln(.54)] / (-0.0001) = t


the half-life of ¹⁴C is 5730 yrs
___ since the skull contains more than half of the original amount, the age should be less than 5730 yr

since the calculated age does not bear this out, it appears that the given value of k is incorrect


using the half life ___ .54 = (1/2)^(t / 5730)

[log(.54)] / [log(1/2)] = t / 5730

{[log(.54)] / [log(1/2)]} * 5730 = t

Answer 4

what about thiss

Answer 5

nope ;-;

Answer 6

whats the answer choices

Answer 7

its a type in answer box

Answer 8

try looking it up

Answer 9

a hiker in africa discovers a skull that contains 63 of its original amount of c-14.
n = n0e-kt
n0= intentional amount of c-14( at time t=0)
n-= amount of c-14 at time t
k=0.0001
t = time, in years
find the age of the skull in the nearest year