help please
@Vocaloid
hm. didn't get the notification from this for some reason. anyway be careful about the exponents the sequence can be written as 10^2 + 1, 10^4 + 1, 10^6 + 1, 10^8 + 1 so you would expect an even exponent not an odd one
so 10^10 + 1?
good
@Vocaloid
using the fact that linear pair angles add up to 180 which statement is ~false~?
D?
good
any ideas? to disprove the conjecture you must select the rectangle with at least 12 square units but w/ a perimeter less than 16 remember that perimeter of a rectangle = 2L + 2W
*meant to say 16 not 14
the top right one?
notice how it has L = 12 and W = 1 perimeter = ?
12?
wait, 14.
perimeter = 2L + 2W = ?
wait, it's the bottom right one.
good
oh i just turned purple!
well you are given perimeter = 2L + 2W = 24 so you would go one by one and see which statement is mathematically impossible remember that L and W must both be greater than 0
is it B? 12x2 is 24, so it goes over
good, B
thank you, want to help with some more?
sure
@Vocaloid
hm. assuming he wants the entire yard fenced it's just perimeter = 2L + 2W
90?
good
this is 6, right?
@Vocaloid
yup good
hm. one foot in ~each~ direction seems to imply that both dimensions are increasing by 2 so new length and width become 5 and 17 calculate the new perimeter
44
good
perimeter = 2L + 2W you are given perimeter and width, therefore 21 = 2L + 2(5) solve for L
11, so would it be like, 6?
you may have forgotten to divide by 2 at the end 21 = 2L + 2(5) 21 - 10 = 2L 2L = 11 so L = 11/2 = ?
11 divided by 2 is 5.5
so the answer is 5.5?
alright
circumference = pi * diameter so you will find the diameter first then multiply by pi note: do not convert pi to its decimal form
A?
remember it has to have pi in the solution somewhere
oh, 3pi then
good
area of triangle = (1/2)b*h you are given b and h, find area
126
perfect
good
alright, i thought that one was the right one
nice
for a square area = side length^2 you are given area, find side length then perimeter = 4 * side length = your sol'n
uh..
so i divide the area?
if you have area = side length^2 how would you find the side length? what's the "opposite" operation of squaring something?
subtraction?
to "undo" a square we would take the ~square root~ of both sides so sqrt(area) = side length find the side length then multiply the result by 4
area = 30.25 so what's the square root of 30.25?
5.5
good then perimeter = 4 * 5.5 = 22 = your sol'n
this one correct?
have to be careful the height is 2 but it's asking for the base not the height
oh, 18?
"the base is 3 times the height"
6 then,
good that's it
well perimeter = 2L + 2W as usual dividing this by 2 we get (1/2)perimeter = L + W so there are two conditions that must be met: 1) the L + W have to add up to (1/2)(30) = 15 2) one dimension must be exactly half the other dimension
any ideas? which answer choice(s) have both dimensions add up to 15?
B?
good attempt but remember the other condition one dimension has to be exactly one half the other
there's only one other candidate that fits both conditions 10 + 5 = 15 in addition, 5 is exactly one half of 10 so 10 by 5 is the only one that could be the solution.
alright..
@Vocaloid
so you'd want the answer choice where every listed combination of dimensions gives area = length*width that is within the bounds of 90 and 130
i got C
that's a good attempt but if we include 12 * 10 in the solution we get 120 which is still within 90 and 130 so A is a more inclusive answer
okay
linear pair = two angles that add up to 180 keep in mind only two angles can be included in a linear pair
|dw:1528837464333:dw|
|dw:1528837701995:dw|
|dw:1528837707424:dw| i see a pair of angles here that add up to 180 with that being said what might the answer be?
also since we're getting close to 100 replies I would recommend closing this question and re-opening a new one after you've figured this one out ^_^ thanks ~
notice how I have circled angle 4 and angle 7 therefore let's try looking for the answer choice that includes angle 4 and angle 7
alright
hm. not quite, it's asking for vertical angles not linear ones|dw:1528839515496:dw|
try to find two angles opposite to each other, that are created by two intersecting lines
|dw:1528839798572:dw|
so it isnt C?
no it is not
|dw:1528839846518:dw|
|dw:1528839852474:dw|
have you tried checking these two angles? <2 and <4?
oh.....
1 and 2 are adjacent, right?
yup good
p needs to be T and ~q f, right?
in order for the end result to be "F," yes
bottom right?
so there's only one condition where the result is F so you should only expect 1 F and the rest being T's
there are only two tables where there are 1 F and 3 T's between those you need to use the aforementioned rule to choose between them
so the bottom left
remember that ~p must be true and ~q must be false so it's the other one
|dw:1528840734734:dw|
bottom left for this one?
good
A for this one?
A would be the intersection between p and q so that would only include the sliver in the middle as a hint, you can describe the blue shaded area as the combination of "not p" or "not q"
*the union of "not p" or "not q"
so it would be B
good
the second one?
hm. not quite (that would be the intersesction /\) for p V q, as long as either p or q is true the result will also be true if they are both false then the result will also be false
alright
for this one, i got D
good
you just have to memorize this, it's true
i got C for this, right?
good
this one is fairly simple, it's also C.
hm. this one is kind of tricky. "Bicycles have two wheels" can be written as "If an object is a bicycle, it has two wheels" making the two wheels part the conclusion the reason why it can't be "it is a bicycle" is that "If an object has two wheels, it is a bicycle" is incorrect (things other than bicycles may have two wheels)
oh, right.
so the two wheels part is the conclusion
oh, alright..
well, this one is B, right?
good
alright! thank you so much!
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