i need my answers checked
@Zarkon
why you think it true ? @ThisGirlPretty
well for a simple reason, the matrices are reversed
yes so and the diagramm ?
than you check the diagramm there is that for x= 2 => y = 8 and the reflection diagramm how is it ?
for y= 2 you see the x = 8 right ?
yeah
so from this result that your answer is correct
@ThisGirlPretty
@Vocaloid
good
@Mercury
hm not quite the given matrix [1 0 0 -1] reflects across the x-axis what image is this?
uh...i dont really know how to read matricies that well..., care to give me a little refresher?
notice how the matrix on the left is \[\left[\begin{matrix}1 & 0 \\ 0 & -1\end{matrix}\right]\] this indicates a reflection across the x-axis from geometry, this is what a reflection across the x-axis looks like:
|dw:1530483866714:dw| notice how the x-axis is acting as the mirror between the two images apply this logic to your problem to see what the correct choice is.
so the first one?
good
good
good
hm. technically none of these are correct because of the order of the matrix multiplication however, since the first two coordinates are positive, that means the first two coordinates should be negative in the reflection therefore C is the only option that could potentially be viable bad question :S
you just need to put the coordinates of X into a 2x3 matrix start by putting the coordinates of X into the first column the coordinates of X are (0,-5) so the first column of the matrix is 0 -5 then keep going across with points Y and Z
oh wait I didn't see you already picked one of the choices whoops the second one is correct
just have to know this one, it's ~center~
remember, for matrices the inner dimensions have to match you have a 1 x 4 multiplied by a 3 x 1 matrix so 4 and 3 (the inner dimensions) are not equal, this matrix product is undefined
not quite it's only rotating the shape 30 degrees counterclockwise (to the left) so see which image takes the triangle and rotates it 30 degrees CC without reflecting it
|dw:1530487567207:dw|
the last one?
|dw:1530487585602:dw|
the tip of the image should be moving left according to this diagram
ah, the first one
good
good
hm not quite start by listing out the dimensions of each matrix, ex: A * B multiplied by C * D then the outer dimensions (in this case, A and D) determine the product dimensions
3x2?
remember dimensions are written as: number of rows * number of columns
for the first matrix how many rows and columns are there?
2 and 3
good so the dimensions of matrix 1 are 2*3 repeat this process w/ the second matrix
3 and 2
good so you have 2*3 by 3*2 so if you look on the outer dimensions you have 2*2 = your sol'n
hm not quite to multiply matrices consider the first row of the first matrix, and the first column of the second matrix: |dw:1530491302194:dw|
|dw:1530491360048:dw|
multiplying the blue gives us (0)(-1) = 0 multiplying the green gives us (-1)(2) = -2 adding these together gives us -2 as the first entry in the product
hm. technically none of the answer choices are actually the correct product what happens if you pick the blank option?
alright can you try repeating this multiplication process with the first row of the first matrix and the second column of the second matrix? the result will let you distinguish what the correct sol'n is
it was the blank one wasnt it?
right
remember that the distributive property is A(B+C) = A*B + A*C what's it called when you can switch the order of multiplication and still get the same product?
commuinative
good so commutative = your sol'n
if i remember, this one is the same, right? 2x2?
good
hm, not quite, remember what we did before first take the first row of the first matrix & the first column of the second matrix
|dw:1530493249161:dw|
then multiply the first terms together then multiply the second terms together
|dw:1530493294588:dw|
giving us (-2)(2) = -4 and (3)(1) = 3 adding these together gives us -1 as the first term not -7
repeat this procedure for the first row of the first matrix and second column of the second matrix
|dw:1530493432342:dw| basically you want to follow this pattern
gonna be eating dinner soon, let me know when you've attempted a solution
i've tried it and got the third one
@Mercury that it?
hm not quite let's redo the last set of multiplication, second row of the first matrix & the second column of the second matrix
we have 3(0) + (-4)(-3) which is 12 not -12 therefore it's the last choice
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