i need some answers checked
@Vocaloid
long time no see, how are you?
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notice how these lines can also be drawn, how many are there? (make sure to count the entire line from end to end)
so she's missing 4?
good
good
hm not quite check your calculations again if it's a parallelogram then BC and AD are equal therefore 2x - 6 = x + 2 first solve for x, then plug it back into AD
since it's a straight horizontal line you just need to count the number of spaces between A and B
so 3?
3? that's a bit too low if that doesn't work try finding the difference between the x-coordinates 6 - (-2) = ?
8
good so 8 = your sol'n going to lunch be back in like half an hour i gues
okay
@Mercury back?
sure what's the next question
good
|dw:1530723814526:dw| try to apply this to your problem and set up the appropriate equation
8000 + 239,000?
then multiply it by 239k?
good, almost there notice that C is the small tangent segment which would correspond to x on your diagram therefore x^2 = 239,000(8000+239,000) solve for x
59033000000
close but that's the value of x^2, simply take the square root of that to get x
2.42?
square root of 59033000000 is 242967 which rounds to 243000 to the nearest thousandth as indicated by the problem directions so 243000 = your sol'n
hm not quite they state that AC and BD are congruent so solve 5x + 5 = 4x + 27 for x then plug into bc
22
good then plug that x back into BC
it's asking for the radius not the diameter |dw:1530726306122:dw| compare your equation to this to see what r would be
7
good
hm not quite for two intersecting chords the angle is the average of the arcs so add the two given arcs & then divide by 2
116
good that's your sol'n
not quite let's start by calculating the length of DB notice that triangle DBA is a right triangle using the pythagorean theorem & the lengths of AD and AB, what's the length of DB?
about like, 190?
notice that AD and AB are only 5 and 10 so 190 is unreasonable
AD is the hypotenuse while DB and AB are the legs therefore AD^2 = DB^2 + AB^2 solve for the length of DB
164?
plugging in the side values 10^2 = DB^2 + 5^2 solve for DB.
ah, alright i got like, 75 x 5
wait, that isnt it..
10^2 = DB^2 + 5^2 subtract 5^2 from both sides
75 and 0?
good so you have 75 = DB^2 solve for DB (leaving in radical form is ok)
notice how you have DB^2 to "undo" a square you just have to take the square root of both sides.
8.66?
so it's 164 then?
good
good
good
?
not quite the volume of the big box is 8 times bigger but that doesn't mean the lengths are the ratio of lengths is the cube root of the volume ratio therefore, find the cube root of 8, then multiply that by the old length
start by finding the cube root of 8.
2
good, so that's the length ratio if the old length is 10, then the bigger length must be 2*10 = 20 = your sol'n
good
volume = (4/3)pi*r^3 so first find the radius then plug it into the formula
so the radius is half th ediameter right?
yes
0.84
that's the radius, now keep going with the rest of the formula
2.48
good but it wants it to the nearest tenth so 2.5
good
hm, check again, remember it wants the one that's false sin = opposite/hypotenuse so A is true try checking B and C
remember cos = adjacent/hypotenuse from the perspective of angle A is cosA = a/c?
yeah?
notice how side a is the opposite from angle A not the adjacent
cosA would be b/c not a/c since side b is the adjacent side
so B is crossed out?
it's looking for the statement that is false since we stated that sinA = b/c not a/c statement B is false making it the only possible answer choice
check your calculations again tan(52) = 12/x
-6.05
make sure your calculator is in degrees mode
1.27
if you have something like A/B = C you can switch B and C to get A/C = B and it's still valid therefore tan(52) = 12/x becomes x = 12/tan(52)
x = 12/tan(52) = ?
you just need to plug this into your calculator, it ends up being 9.4
so that's the solution?
yes.
good
not quite check your calculations again you just need to break down the shape into the three rectangles given and calculate the area of each rectangle
left rectangle: dimensions: 9 and 6 middle rectangle: dimensions: 5 and 4.5 right rectangle: dimensions: 7.5 and 13 remember that are of a rectangle is L*W
alright,,
so i just multiply all those up?
calculate the area of each rectangle individually, then add the three areas up.
9x 6=54 5 x 4.5 =22.5 7.5 x 13 = 97.5
now add them up
174
good so 174 = your sol'n
hm not quite, check your calculations again sum of exterior angles is 360 so 2x + 4x + 13 + x + (5x-13) = 360 solve for x
good
for a shape to be a parallelogram ~opposite~ sides need to be congruent not adjacent ones so the shape shown is a kite not a parallelogram making the original statement false
you don't know any angles so law of sines does not apply here
good
hm not quite a full circle is 360 degrees if he only ran 152 degrees of the full arc he ran (152/360) of the way there multiply (152)*360 by the circumference to get the solution
5470
*should be (152/360) not 152*360
so (152/360)*circumference
0.42
circumference = 2 * 3.14 * r (152/360) * 2 * (3.14) * r = ?
3.2
good so 3.2 = your sol'n
|dw:1530735819134:dw| not quite, check your calculations again
try to use the diagram to see what the arc would be given your angle A
notice how the arc is twice the length of the angle
so it's double 35?
yes
70
good
those circles are not tangent |dw:1530736272235:dw| to be internally tangent both circles need to share the same tangent line and one circle is inside the other
good
not quite in a rhombus the diagonals bisect each other so NL is just one half of JL now, you have a right triangle on the lower right corner with legs NK and NL, and hypotenuse KL solve for NK
19.5?
that's the value of NL, keep going
so...19.5 divide the hypot?
you have a right triangle with legs NK and NL and hypotenuse KL plug these into the pythagorean theorem and solve for NK
notice, that according to the diagram, KL = JK
as we stated before, KL = JK which equals 21 NL = 19.5 therefore NK^2 + NL^2 = KL^2 NK + 19.5^2 = 21^2 solve for NK.
60.75
almost, that's NK^2 so just take the square root of that and round to the nearest 10th
8.0
sqrt(60.75) is about 7.79 which rounds to 7.8 not 8
hm not quite you can still make a square if you cut like this |dw:1530738309245:dw|
|dw:1530738443348:dw| this is hard to visualize but you can also get a trapezoid as the cross section if you tilt the angle a bit so pentagon is the only one you can't make
it's asking for which one you can't make so pentagon = your sol'n
good
in general angles around a vertex are always equal to 360 |dw:1530740571061:dw|
since the logo uses two diff. shapes by definition it's not regular and thus the third statement is false
hm not quite if you notice the line RS can be the hypotenuse of a right triangle with legs 1 and 3, what's the hypotenuse?
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6?
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if a and b are the legs and c is the hypotenuse what is the hypotenuse if the legs are 3 and 1?
"the legs are 3 and 1" "a and b are the legs" therefore a and b are 3 and 1 solve for c
the formula states that c^2 = a^2 + b^2 plug in a and b into the formula and solve for c.
we have stated that a and b are equal to 3 and 1 therefore c^2 = 1^2 + 3^2 solve for c.
10?
notice how the formula gives c^2 not c so you have to take the square root at the end (radical form is ok, let's leave it as sqrt(10))
now repeat this process with ST
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|dw:1530742863701:dw|
calculate the hypotenuse ST of this right triangle in red
if you are having trouble please use our previous calculations of RS as a reference guide
5,5?
we have a right triangle with legs 2 and 6 use the pythagorean theorem to calculate the hypotenuse
as we stated before a^2 + b^2 = c^2 a and b are the legs plug in the legs and find the hypotenuse (c)
40
so 20
c^2 = 40 therefore c is the sqrt(40) now we have the two legs of the big triangle area of triangle = (1/2)BH = (1/2)sqrt(40) * sqrt(10) = ?
A?
plug (1/2)sqrt(40) * sqrt(10) into a calculator be careful with parentheses
(1/2) * sqrt(40) * sqrt(10) = (1/2) * sqrt(400) = ?
you just need to calculate the square root of 400 and divide it by 2.
10
good so 10 = your sol'n
nvm it's 8
let's use a square with side length s the perimeter is 4s if we double each side (k = 2) to get the new side length 2s perimeter = 4(2s) = 8s so the perimeter increases by a factor of k not 2k
check again the entire line is 10 units how long is the segment RT?
4
good so the probability is 4/10 not 3/10 or in other words, 2/5
hm not quite each side is 8 by 8 so each side = 64 ft^2 assuming he only paints the outer four walls, 64 * 4 then divide by 20 since each paint bucket is 20 ft^2 of paint
12.8
good but since we can only buy whole paint buckets round up to 13= your sol'n
good
good
you cannot use triangle sum because you only have one angle known you have the opposite and adjacent sides, which trig ratio is this?
cos?
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notice how tan has opposite and adjacent so only the first choice is applicable
going to be having dinner see you in a bit
good
it would be a good idea to close this and start on a new question
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