12 hours until course finishes. helpme
Graph these first Do you know how to algebraiclly solve for them?
Well, I want to learn how to do it, but I also need to learn quick. So can you just outline all the steps, i'll figure out the answer myself probably.
@dude @Vocaloid
This is just the review test, not the actual test.
I just need to learn how to solve it.
For part A, the solution is anywhere where they intersect or when they equal the same thing
~~When x is -2, they both will equal 4~~
Okay
Table for \(y=2^{-x}\)
Table for \(\large y=4^{x+3}\)
These can be obtained by substituting any value (-3, -2,- 1, 0, 1, 2, 3) in for x
ie. \(y=2^{-x}\) Substitute 0 for x \(y=2^{-0}\) =>\(y=2^0\) Anything to the 0 power is just 1 so... \(y=2^{-0}=1\)
crap i dont have time for qc, cya
Okay
ill just read through my lessons
Okay D:
sozz
rip. bro just plug and chug
or look at the graph which is like 2x easier
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