Question

Express your answer in complete form in order of orbital filling. For example, 1s22s2 should be entered as 1s^22s^2.

Answer 1

1s^22s^22p^63s^23p^64s^23d^104p^65s^24d^105p^66s^2

Answer 2

?

Answer 3

what element is this?

Answer 4

Mg

Answer 5

yeah, Magnesium only has 12 electrons so I think you went a little too far

Answer 6

last orbital should be 3s^2 then it stops there

Answer 7

What does it mean when an electron is anomalous

Answer 8

anomalous electron configuration means it differs from what you expect (copper and chromium are two common examples)

Answer 9

does it still have to do with the normal electron configuration or is it altered in some way

Answer 10

like, for copper you would expect

[Ar] 4s2 3d9
using the normal method, but copper likes having a full d-orbital set so it will take one of the 4s electrons and move it back down to get

[Ar] 4s1 3d10
as the actual configuration

Answer 11

(keep forgetting that 4s comes before 3d10 whoops)

Answer 12

that's an example of an anomalous configuration

Answer 13

Like its asking for the configuration of Mo (anomalous) it would be

Answer 14

1s^2
2s^2
2p^6
3s^2
3p^6
4s^2
3d^14
4p^6
5s^2

Answer 15

i moved the remaining 4 to the 3d^10 orbital making it 3d^14

Answer 16

yeah, the d-subshell can only take 10

Answer 17

1s^2
2s^2
2p^6
3s^2
3p^6
4s^2
3d^10
4p^6
5s^2
4d^4

Answer 18

But then how would I alter this

Answer 19

let's use [Kr] as a place-holder for the electron configuration of Krypton

[Kr] 5s2 4d4 would be the normal electron configuration

the d-subshell has 5 orbitals, if we move one of the electrons from the 5s to the 4d we can get 1 electron in each d orbital

[Kr] 5s1 4d5 should do it

Answer 20

writing out the full configuration we get

1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 5s1 4d5

Answer 21

oh okay so it basically balances the configuration out so that each orbital is filled

Answer 22

yeah, sort of

Answer 23

most of the time you will be trying to fill up the p-subshell or the d-subshell