3x^2y + 4x y + 1 - 5x^4y -6y descending order
You want to have the exponent to go from highest to lowest ex. \(x^3+x^2+x^1\)
alright so wouldnt 4xy come first?
This is the equation right? \(3x^2y + 4x y + 1 - 5x^4y -6y\)
yes
Not quite, you want to look at the exponent (that tiny number above)
ok so 5x^4, because that one has the highest exponent
Right
\(−5x^4y\)* its 1 term
so that would come first even though it has a - in front of it?
The - or positive does not matter, the only thing that matters is the exponent
ohhhh ok that makes more sense now
Yeh
-5x^y + 3x^2y?
Yep
then would + 4xy come next or -6y
neither of them have an exponent so how would u decide which one is next
4xy because it continus the pattern with the terms having xy \(- 5 {\color{red}{x}}^4\color{red}{y}+3\color{red}{x}^2\color{red}{y}\) + \(4\color{red}{xy}\)
ohh ok then it would be +1 because that is a increasing expression?
The value without a variable goes last
ok so -6y is next because it has a "invisible number' or
well variable
Yeah it doesnt have an x variable \(- 5x^4y+3x^2y+4xy -6y+1 \)
ok thank you so much really helped
Of course
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