Lines EH and FG are parallel, and ABC is an equilateral triangle. the measurement of angle CDF divided by the measure of angle BAG is equal to the measure of angle CBE divided by the measure of angle CAD. expressing your answer as a simplified improper fraction, what is the measure of angle CDF divided by the measure of angle BAG?
@Vocaloid
@dude
Have you drawn this out?
@smokeybrown @Vocaloid If you guys are free. I’m pooped from this 2hr lecture ._.
hello?
I'm in the middle of trying to solve for BAG. The numbers are looking a little wonky, but let me see if what I get makes sense
I'm uploading my work in a moment, but I got a ratio of 1.5 as my answer...
Sorry if it's a bit hard to make out. Basically, I established a relationship between angles B and D and angles A and C (I labelled the angles differently because I found it easier). B is 180-D because they are (is it the right term?) opposite interior angles. C is 120-A because the angles lie on the same line, which must add up to 180 degrees, but a section of that arc is already taken by the 60 degree angle in the equilateral triangle, leaving 120. After that, I wrote out the equation, substituting B and C for their A and D equivalencies, cross-multiplied, and solved for the ratio.
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