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Mathematics 20 Online
zarkam21:

determine the derivative of f(x)=arctan x

zarkam21:

@Vocaloid

zarkam21:

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zarkam21:

Thsi is what I have so far

Vocaloid:

All the way up to df/x = 1/sec^2(x) is good From there use a trig identity to rewrite sec(f) in terms of tan(f) Then since f = arctan(x) then x = tan(f) so you can replace tan(f) with x

Vocaloid:

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zarkam21:

sin/cos ?

Vocaloid:

sec^2(theta) = 1 + tan^2(theta) Apply this logic to your denominator

zarkam21:

denominator as in sec^2(f)

Vocaloid:

Yes

zarkam21:

ec^2(f) = 1 + tan^2(f)

zarkam21:

and then it would condense down to

zarkam21:

arctan x ?

Vocaloid:

Good Then as we stated before, tan(f) = x so plug that in for tan^2(f) to get th final derivative

zarkam21:

sec^2(f) = 1 + tan^2(x)

Vocaloid:

Your new denominator is 1 + tan^2(f) Replacing tan(f) with x gives us 1 + x^2 as the new denominator

Vocaloid:

And that’s it, the derivative is 1/(1+x^2)

Vocaloid:

Anyway I can’t really stay but will try to be on later

zarkam21:

SOunds good see you tonight

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