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zarkam21:
determine the derivative of f(x)=arctan x
7 years ago
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zarkam21:
@Vocaloid
7 years ago
zarkam21:
7 years ago
zarkam21:
Thsi is what I have so far
7 years ago
Vocaloid:
All the way up to df/x = 1/sec^2(x) is good
From there use a trig identity to rewrite sec(f) in terms of tan(f)
Then since f = arctan(x) then x = tan(f) so you can replace tan(f) with x
7 years ago
Vocaloid:
7 years ago
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zarkam21:
sin/cos ?
7 years ago
Vocaloid:
sec^2(theta) = 1 + tan^2(theta)
Apply this logic to your denominator
7 years ago
zarkam21:
denominator as in sec^2(f)
7 years ago
Vocaloid:
Yes
7 years ago
zarkam21:
ec^2(f) = 1 + tan^2(f)
7 years ago
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zarkam21:
and then it would condense down to
7 years ago
zarkam21:
arctan x ?
7 years ago
Vocaloid:
Good
Then as we stated before, tan(f) = x so plug that in for tan^2(f) to get th final derivative
7 years ago
zarkam21:
sec^2(f) = 1 + tan^2(x)
7 years ago
Vocaloid:
Your new denominator is 1 + tan^2(f)
Replacing tan(f) with x gives us
1 + x^2 as the new denominator
7 years ago
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Vocaloid:
And that’s it, the derivative is 1/(1+x^2)
7 years ago
Vocaloid:
Anyway I can’t really stay but will try to be on later
7 years ago
zarkam21:
SOunds good see you tonight
7 years ago
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