determine the derivative of f(x)=arctan x
@Vocaloid
Thsi is what I have so far
All the way up to df/x = 1/sec^2(x) is good From there use a trig identity to rewrite sec(f) in terms of tan(f) Then since f = arctan(x) then x = tan(f) so you can replace tan(f) with x
sin/cos ?
sec^2(theta) = 1 + tan^2(theta) Apply this logic to your denominator
denominator as in sec^2(f)
Yes
ec^2(f) = 1 + tan^2(f)
and then it would condense down to
arctan x ?
Good Then as we stated before, tan(f) = x so plug that in for tan^2(f) to get th final derivative
sec^2(f) = 1 + tan^2(x)
Your new denominator is 1 + tan^2(f) Replacing tan(f) with x gives us 1 + x^2 as the new denominator
And that’s it, the derivative is 1/(1+x^2)
Anyway I can’t really stay but will try to be on later
SOunds good see you tonight
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