https://prnt.sc/lenwd0

Question

johnnn · Answer

@dude

dude · Answer

Okay first off, line EB does not even seem to intersect G, I guess we're assuming they do

Also, you always want to start out with the given

johnnn · Answer

okay so then what? lol

dude · Answer

Oh wait, you just need 1 statement and and proof?

johnnn · Answer

"this proof is worth 30 points, 15 points for statements , 15 points for reasons"
thats what it says

johnnn · Answer

@Shadow

563blackghost · Answer

So this requires a two column proof.

First list your givens.

$\bf{Given:m\angle EGF=60^{o}~and~m\angle AGF=90^{o}}$

Your visual is as followed:

|dw:1541434183463:dw|

Viewing it you would see that EGB is a straight line meaning $\bf{\angle EGB = 180^{o}}$ based on definition of a straight line. You are shown that $\bf{\angle AGF}$, $\bf{\angle FGE}$ and $\bf{\angle AGB}$ lie on a straight line. So it would follow as $\large\bf{\angle AGF+\angle FGE + \angle AGB=180}$ Substitute.

$\bf{90+60+\angle AGB=180}$
add.

$\bf{150+\angle AGB=180}$
follow by subtraction property of equality.

$\bf{180-150=\angle AGB}$
simplify.

$\bf{30=\angle AGB}$

johnnn · Answer

okay so should i just put all that as the answer? lol

563blackghost · Answer

well do you understand the process?

johnnn · Answer

yes

563blackghost · Answer

den yes you do, just make sure you understand it, if you dont let me know i can break it down more if you want.

johnnn · Answer

can you break the each section? tell me whats the reason, whats the proof and etc. thank you so much