Ask your own question, for FREE!
Mathematics 16 Online
Vocaloid:

math q on behalf of nicole

Vocaloid:

|dw:1542162070086:dw|

Vocaloid:

@Nicole

Nicole:

thank you

Vocaloid:

any ideas? as a hint, if you want to move something from the numerator to the denominator (or from the denominator to the numerator) you need to multiply the exponent by -1

Nicole:

so 4 *-1

Nicole:

thats -4

Vocaloid:

yes, so if you want to move x^4 to the numerator you would write x^(-4) in the numerator

Nicole:

A and B contains that

Vocaloid:

good B works because they applied the same logic to 5 and 6 so A+B are your solutions

Nicole:

got it http://prntscr.com/li2p2m

Vocaloid:

any ideas? when multiplying the same base over and over, add the exponents

Nicole:

all the exponents added to each other is -2

Nicole:

so D?

Vocaloid:

the exponent is applied to m so m^(-2) should be in your solution somewhere

Nicole:

A? im thinking

Vocaloid:

m^(-2) is equivalent to 1/m^2

Nicole:

wouldnt it be A since the numerator is 1?

Nicole:

and its negative

Vocaloid:

pay attention to the exponent on m A has 1/m^90 not 1/m^2

Vocaloid:

the exponent on m must be positive 2 if its' in the denominator or negative 2 if its in the numerator, since we concluded m^(-2) as part of the solution

Nicole:

ohh so C

Vocaloid:

yes

Nicole:

http://prntscr.com/li2pkc

Vocaloid:

any ideas? remember when you raise an exponent to another exponent, multiply the exponents so it ends up being 4^(-3) * x^(-2*3) = ? which answer choice is mathematically equivalent?

Nicole:

D

Vocaloid:

good

Nicole:

http://prntscr.com/li2rbj

Vocaloid:

any ideas? when dividing the same base, subtract the exponents so start with the 9/3 part first, then the x^8/x^4 part

Nicole:

so 8-4?

Nicole:

which is 4

Vocaloid:

good, so 3x^4 = your sol'n

Nicole:

so B

Vocaloid:

yup

Nicole:

http://prntscr.com/li2ryz

Vocaloid:

generally in scientific notation the n part has to be a decimal or whole # not a fraction p has to be an integer that being said any ideas?

Nicole:

D might be one

Vocaloid:

good and if p is an integer, then 10 is naturally a possibility so C+D are my best bet

Nicole:

okayy http://prntscr.com/li2sgp

Vocaloid:

any ideas? n * 10^(x) the n part has to be between 1-10, and with that being said, what do you think is the solution?

Vocaloid:

(or between -1 and -10)

Nicole:

so its not B

Nicole:

which makes the answer b LOL

Vocaloid:

remember it's asking for the one ~not~ in scientific notationo so B must be your solution, since the 12.7 part isn't between 1-10

Vocaloid:

yup

Nicole:

one more after http://prntscr.com/li2t3b

Vocaloid:

so basically we need to convert both to the same exponent we can re-write 1.26*10^(-3) by multiplying the 10^(-3) part by 10^9, and dividing the 1.26 part by 10^9 (so the number still says the same, just with the exponent 10^6 instead of 10^(-3)

Vocaloid:

so doing this, we get (0.00000000126 * 10^6) - 7.003*10^6 so after that it's just simple subtraction of (0.00000000126 - 7.003)*10^6

Vocaloid:

actually come to think of it you don't need to do the subtraction

Nicole:

its going to be 7 something?

Vocaloid:

just re-write 1.26*10^(-3) in standard form and see whether it matches up with B or D

Nicole:

http://prntscr.com/li2ule

Nicole:

that is it in standard form^

Vocaloid:

so basically, we can take 1.26*10^(-3) and move the decimal point 3 places to the left (since we have -3 as the exponent) to get 0.00126 which can only match up with expression D

Nicole:

ohhh okay last one http://prntscr.com/li2v9l

Vocaloid:

any ideas? to multiply 10^3 * 10^7 we add the exponents ( be careful, you are only adding the exponents not the entire expressions together)

Nicole:

3+7= 10

Vocaloid:

good so your solution must have 10^(3+7) not 10^3 + 10^7 somewhere

Nicole:

A

Vocaloid:

good

Nicole:

okay thank you!!! i got them all right

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!