Question

http://prntscr.com/mcamim

Answer 1

@Vocaloid

Answer 2

Hi there,
Have you attempted to answer this? What have you come up with?

Answer 3

Im thinking A

Answer 4

That's right

Answer 5

Ohh okay lol how about this:

http://prntscr.com/mcaovh

having a bit trouble with this one

Answer 6

@Hero @Vocaloid @Ultrilliam

Answer 7

@SmokeyBrown anyone?? loll

Answer 8

You can just change the order that they are being multiplied

So the decimals multiplied by each other and the exponents as well (remember the same base exponents rule)

\(b^n\cdot b^m=b^{n+m}\)

Answer 9

so C?

Answer 10

@Vocaloid

Answer 11

yeah

Answer 12

http://prntscr.com/mcb88n

Answer 13

starting value is 2 and the growth factor is 3 since the values are tripling each time

try to think of how to express this as an exponential function

Answer 14

B?

Answer 15

good

Answer 16

http://prntscr.com/mcb98d

Answer 17

really need to start remembering these, but remember, translating up by 4 means adding 4 to the entire function

Answer 18

Ohh okay got it so it would be X

Answer 19

C*

Answer 20

yes

Answer 21

http://prntscr.com/mcbakx

Answer 22

B is the growth factor, since it's the thing being raised to x

in interest functions the growth factor is 1 + (the interest rate as a decimal)

Answer 23

so 1.3 +1 ?

Answer 24

"interest rate as a decimal" so convert 1.3% to a decimal first

Answer 25

0.013

Answer 26

good, so 1 + 0.013 is your B-term

Answer 27

plus 1 so C

Answer 28

good

Answer 29

http://prntscr.com/mcbc85

Answer 30

ok, so for these problems you want to factor out as many perfect squares as you can

so for 12, you can re-write this as 4*3 and factor out sqrt(4) which is 2, leaving sqrt(3) as part of the solution

repeat this logic for the x and y terms

Answer 31

hmm if its leaving sqrt(3), then wouldnt it be B?

Answer 32

yeah

Answer 33

http://prntscr.com/mcbdfo

Answer 34

for both 75 and 12 factor out as many perfect squares as you can. as a hint you should end up with ___ * sqrt(3) for both of them, where the coefficient goes into the blank

Answer 35

after that you'll have two like terms

Answer 36

but when you simplify it wouldnt it be \[3\sqrt{3}\]

Answer 37

oh whoops I didn't see you already chose a solution

yeah question 4 is right, for question 5 check again, the exponent goes in the numerator and the root goes in the denominator

Answer 38

oh so A

Answer 39

good

Answer 40

http://prntscr.com/mcbfqe

Answer 41

just pick one point to be your (x1,y1) and the other one to be your (x2,y2) it doesn't matter as long as you are consistent

Answer 42

so (7,9) and (-3,2)

Answer 43

yes then assign your x1, y1, etc. and plug them into the distance formula

Answer 44

so

\[d=\sqrt{(-3-7)^2+(2-9)^2}\]

Answer 45

like that?

Answer 46

ah, no, be careful about what you're plugging in

if (x1,y1) = (7,-3) and (x2,y2) = (9,2)

then (x2-x1) = (9-7) and (y2-y1) = (2- (-3))

Answer 47

Ohhh okay , then what do I do

Answer 48

continue plugging them into the formula

Answer 49

x1 = 7
y1 = -3
x2 = 9
y2 = 2

Answer 50

\[d=\sqrt{(9-7)+(2- (-3)}\]

like this?

Answer 51

you forgot the exponents but you're on the right track

Answer 52

if you look @ the formula there are squares around the parentheses

Answer 53

\[d=\sqrt{(9-7)^2+(2- (-3)^2}\]

this?

Answer 54

almost just stick a closed parentheses after (-3) and then evaluate that

Answer 55

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Nicole
\[d=\sqrt{(9-7)^2+(2- (-3))^2}\]

should do it

Answer 56

so i have to solve that?

Answer 57

yes, just use order of operations

Answer 58

\[\sqrt{29}\] is the answer so C

Answer 59

good

Answer 60

http://prntscr.com/mcblh6

Answer 61

I solved it and got B? is it correct?

Answer 62

yes

Answer 63

http://prntscr.com/mcbmil

Answer 64

a^2 + b^2 = c^2

where a and b are the legs, and c is the hypotenuse

Answer 65

nvm the answer you chose is correct

Answer 66

http://prntscr.com/mcbn11

Answer 67

40 is good

for 41 just plug in both solutions, one of them will be valid and the other extraneous one won't work when you plug it back into the original problem

Answer 68

Hmm im thinking C but im really not that sure

Answer 69

sqrt(x+5) = x -1

notice how x = -1 gives us

sqrt(-1+5) = -2

square roots of real #'s cannot be negative making x = -1 the extraneous one

Answer 70

is x=4 extraneous too?

Answer 71

try plugging it in and see if both sides are equal or not.

Answer 72

No its not its valid so D

Answer 73

or wait

Answer 74

sqrt(x+5) = x - 1

if x = 4

sqrt(4+5) = 4 - 1

both sides are equal to 3. so x = 4 is a valid solution.

Answer 75

Yeah thats what I got too so D

Answer 76

good

Answer 77

http://prntscr.com/mcbpqz

Answer 78

they give you the formula for d and they give you A so just plug A into the formula.

Answer 79

d=16 so A

Answer 80

good

Answer 81

http://prntscr.com/mcbt2i

Answer 82

the usual approach with these types of problems is to set the denominator equal to 0 and solve for x.

Answer 83

how can I set the denominator equal to 0?

Answer 84

copy the denominator

write an equals sign

then put 0 on the end

Answer 85

B?

Answer 86

good

Answer 87

http://prntscr.com/mcbvp8

Answer 88

try 46 again, there's no way to get (x+6)^2 because there's only one place where (x+6) shows up

Answer 89

hmm Im stuck in between B and C

Answer 90

what do you get when you divide 3x^2/5x?

Answer 91

3x/5

Answer 92

good so you should have x somewhere in the numerator

Answer 93

oh so C

Answer 94

good

Answer 95

http://prntscr.com/mcbxkm

Answer 96

both are good

Answer 97

http://prntscr.com/mcbytv

last two for today loll

Answer 98

both of the denominators have x so leave that alone

just find the LCM of 5 and 7

Answer 99

for question 50 just cross multiply

Answer 100

for 49 its, 35 so A?

and 50 its A?

Answer 101

don't forget the x, ---> 35x

Answer 102

50 is good

Answer 103

Okay thank you so much voca! Goodnight