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Mathematics 21 Online
mhchen:

Where's the problem in this solution:

mhchen:

I will prove \[a^{n-1} = 1\] Where a is any non-zero number and n is any natural number, using induction. Let P(n) be the sentence \[a^{n-1} = 1\] BASE CASE: P(1): \[a^{1-1} = a^{0} = 1 \] INDUCTION: Suppose P(1), P(2), ...P(n) is all true, I wish to prove P(n+1) is also true. \[a^{(n+1)-1} = a^n = a^n*\frac{a^{n-2}}{a^{n-2}} = \frac{a^{n-1}*a^{n-1}}{a^{n-2}} = \frac{1*1}{1} = 1\] Where's the error?

jhonyy9:

- the denominator of this fraction with a^(n-2) so you need rewriting it in the form of a^(n-1) *a^(n-1) like in numerator hope helped

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