Question

coulumb's law part two

Answer 1

@Shadow

Answer 2

Well you'd just solve for the force in each direction then sum them.

Answer 3

Since all the numbers are the same, you'd only need to do it once.

Answer 4

\[F_{e} = \sqrt (F_{x}^2 + F_{y}^2 )\]

Answer 5

-2.048N

Answer 6

ok wth

Answer 7

Okay let me see if that's correct

Answer 8

ok i give up ily but i wanna sleep thanks

Answer 9

I got the same force, but keep in mind that's just the attractive force between Q1 and Q3 or Q2 and Q3.

Answer 10

It's just one last easy step.

Answer 11

oh so you multiply that value by two

Answer 12

We take -2.048 and then square it, then multiply it by two, since the forces in each direction are the same magnitude and direction (since they are same distance, charge, etc).

Answer 13

Then take the square root of that

Answer 14

2.896 N

Answer 15

good job, easy

Answer 16

By the way, this is my guide: https://questioncove.com/study#/updates/5ae2784b1b352b3acc334c00

Answer 17

For when the exam comes up.

Answer 18

thanks