Question

http://prntscr.com/next0q

Answer 1

@Narad

Answer 2

@Vocaloid

Answer 3

Assuming the equation they gave you was, \(y=a\sqrt{x-b}+k\)

A is the vertical dilation
b is the horizontal translation
k is the vertical translation


I am not for sure what equation they taught you so it would be useful to include the general equation they gave you

Answer 4

so 4 is the vertical dilation...

like what am I supposed to put for this question lol

Answer 5

and they did not give me a general equation...thats all they gave me

Answer 6

@Narad any input please? or @Vocaloid

Answer 7

I would write the function as
\[y=4\sqrt{x-1} -1\]
b will translate the curve to the right by one unit
a will scale 4 times in the y direction
k will translate the curve by one unit downwards
Hope that this will help!!!

Answer 8

thank you!

http://prntscr.com/neysnr

Answer 9

The new function is
\[y=3 \sqrt{(x-3)}+2\]
b will translate the curve by 1 unit to the right
a will scale the function 3 times in the y-direction
k will translate the curve by 2 units upwards

Answer 10

Got it thanks for that

can you just check these pls
http://prntscr.com/neyve7

Answer 11

\[y=\sqrt{(5x)}\]
Scaling 5 times in the y-direction

Nº27
\[y=\sqrt{4x}-2\]
Scaling 4 times in the y-direction
Translation down by 2 units

Answer 12

\[y=a f(h(x+b)) +k\]

Answer 13

Ohh okay

http://prntscr.com/neyxll

Answer 14

In the y-direction upwards

Answer 15

http://prntscr.com/nez13d

Answer 16

The domain is
\[3x+9 \ge 0 => x \ge-3\]
\[x \in [-3, \infty )\]
When x=-3 ; y=-1
\[x=\infty => y=\]
The range is
\[f(x)= y \in [-1, +\infty )\]

Answer 17

Got it thank you!

Answer 18

You are welcome