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@Narad
xlog7=log124 x=log124/log7=2.48
How can we check that? because it says we also need to check it
ok \[7^{2.48}=124.7\]
(x-3)log(6)=log(52) x-3=log(52)/log(6) x-3=2.21 x=5.21
okay how about when we check it?
\[6^{5.21-3}=52.4\]
\[(x+4)\log _{10}(10)=\log _{10}1000\]
x+4=3 x=-1
Check : \[10^{-1+4}=10^{3}=1000\]
\[\log _{5}x=3\] \[5^{3}=x\] \[x=125\]
check?
\[\log _{5}125=\log _{5}5^{3}=3\]
\[\log _{2}(x-3)=5\] \[x-3=2^{5}=32\] \[x=32+3=35\] Check \[\log _{2}(35-3)=\log _{2}32=\log _{2}2^{5}=5\]
\[3\log _{6}(x+1)=9\] \[\log _{6}(x+1)=3\] \[x+1=6^{3}=216\] x=215 check \[3\log _{6}(215+1)=3\log _{6}216=3\log _{6}6^{3}=3*3=9\]
\[\log _{5}(2x)-5=-4\] \[\log _{5}(2x)=-4+5=1\] \[2x=5^{1}=5\] x=2.5 Check\[\log _{5}(2*2.5)-5=\log _{5}5-5=1-5=-4\] LHS =RHS
\[3(5)^{2x-3}=6\] \[3*5^{2x-3}=6\] \[5^{2x-3}=6/3=2\] \[(2x-3)\log5=\log2\] \[2x-3=\log(2)/\log5=0.43\] \[2x=3.43\] x=1.72 Check \[3*5^{2*1.72-3}=5.99\] LHS =RHS
\[2^{x-4}+10=22\] \[2^{x-4}=22-10=12\] \[x-4=\log12/\log2\] x-4=3.58 x=7.58 check \[2^{7.58-4}+10=22\] LHS = RHS
\[\log _{3}3+\log _{3}x=\log _{3}(3x)=5\] \[3x=3^{5}=243\] x=243/3=81 Check \[\log _{3}3+\log _{3}81=\log _{3}243=\log _{3}3^{5}=5\] LHS=RHS
okay can you help me with a couple more pls?
yes
True
2
-4.7
\[0.252^{x}=41\] \[xlog(0.252)=\log41\] \[x=\log41/\log0.252=-2.69\] Check \[0.252^{-2.69}=40.8\] LHS=RHS
Option D
\[2lnx+2=1\] \[2lnx=2-1=1\] \[lnx=1/2\] \[x=e ^{1/2}\] x=1.65 This does not fit in the options
hmm
I make the corrections \[lnx=-1/2\] \[x=e ^{-1/2}\] x=0.61 answer is option B
\[x=\log _{3}15\] \[=\ln(15)/\ln(3)=2.46\] answer is option C
@Narad
\[logx=\log(4x-9)\] \[x=4x-9\] \[3x=9\] x=3 Check \[\log(4*3-9)=\log3=logx\] RHS=LHS
Answer is option A
@Narad
\[7*6^{3.05}=1653.7 \neq 64\] The answer is FALSE
Nº2 correct nº3 correct nº4 correct
nº1 true nº2 if you write y=1/x as \[y=x ^{-1}\] you can sider y=1/x as an exponential function, TRUE
nº2 no because it's not something to the power of x, it's FALSE
nº3 and nº4 are both TRUE
nº12 \[y=Ae ^{bx}\] \[b <1\] No it's not an exponentila decay FALSE nº13 option C reflection in the x axis and a shift downwards by 2 units
nº16 the domain is \[\mathbb{R} \] option A nº17 option C \[y > 2\] nº18 Population is \[p=567(1+0.0015*9)=574\] if it's calculated like a simple interest otherwie, \[p=567(1+0.0015)^{9}=574\] it's the same answer
nº19 the population is \[P=100000*(1+0.045)^{5}=124618\] Nº18 there is a correction \[p=567*(1+0.015)^{9}= 648\]
\[y=2^{x+1.6}\]
\[y=(1/2)^{x-1}\]
\[f(x)=\log(x)\] \[g(x)=alog(x)\] The answer is option D
nº26 The domain is option B nº27 The range is all real numbers, option A nº28\[1.5^{3.8}=4.7\neq7\] The answer is FALSE nº29 \[x=\log _{2}100 = \ln100/\ln2=6.64\]
option B
nº35 A horizontal shift by 3 units to the right and a vertical shift up by 5 units
nº36 a horizontal shift by 3 units to the left and a vertical shift up by 2 uints
nº37 3399 $ nº38 \[f(x)=logx\] \[g(x)=\log(x-h)\] The answer is option C nº39 The domain is x>-3
nº40 \[2.4^{3.75}=26.7 \neq9\] The answer is FALSE nº41 \[3^{x+1}=500\] \[x+1=\log500/\log3=5.66\] x=5.66-1=4.66
okay thank you so much for the help
You are welcome
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