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Mathematics 21 Online
Nicole:

http://prntscr.com/nmhfue

Nicole:

@Narad

Narad:

xlog7=log124 x=log124/log7=2.48

Nicole:

How can we check that? because it says we also need to check it

Narad:

ok \[7^{2.48}=124.7\]

Nicole:

okay http://prntscr.com/nmhlcy

Narad:

(x-3)log(6)=log(52) x-3=log(52)/log(6) x-3=2.21 x=5.21

Nicole:

okay how about when we check it?

Narad:

\[6^{5.21-3}=52.4\]

Nicole:

okay http://prntscr.com/nmhngw

Narad:

\[(x+4)\log _{10}(10)=\log _{10}1000\]

Narad:

x+4=3 x=-1

Narad:

Check : \[10^{-1+4}=10^{3}=1000\]

Nicole:

Okay http://prntscr.com/nmhpj2

Narad:

\[\log _{5}x=3\] \[5^{3}=x\] \[x=125\]

Nicole:

check?

Narad:

\[\log _{5}125=\log _{5}5^{3}=3\]

Nicole:

okay http://prntscr.com/nmhs6x

Narad:

\[\log _{2}(x-3)=5\] \[x-3=2^{5}=32\] \[x=32+3=35\] Check \[\log _{2}(35-3)=\log _{2}32=\log _{2}2^{5}=5\]

Nicole:

okay http://prntscr.com/nmhto9

Narad:

\[3\log _{6}(x+1)=9\] \[\log _{6}(x+1)=3\] \[x+1=6^{3}=216\] x=215 check \[3\log _{6}(215+1)=3\log _{6}216=3\log _{6}6^{3}=3*3=9\]

Nicole:

Okay http://prntscr.com/nmhuyy

Narad:

\[\log _{5}(2x)-5=-4\] \[\log _{5}(2x)=-4+5=1\] \[2x=5^{1}=5\] x=2.5 Check\[\log _{5}(2*2.5)-5=\log _{5}5-5=1-5=-4\] LHS =RHS

Nicole:

Okay http://prntscr.com/nmic6z

Narad:

\[3(5)^{2x-3}=6\] \[3*5^{2x-3}=6\] \[5^{2x-3}=6/3=2\] \[(2x-3)\log5=\log2\] \[2x-3=\log(2)/\log5=0.43\] \[2x=3.43\] x=1.72 Check \[3*5^{2*1.72-3}=5.99\] LHS =RHS

Nicole:

Okay http://prntscr.com/nmid8g

Narad:

\[2^{x-4}+10=22\] \[2^{x-4}=22-10=12\] \[x-4=\log12/\log2\] x-4=3.58 x=7.58 check \[2^{7.58-4}+10=22\] LHS = RHS

Nicole:

Got it http://prntscr.com/nmigfm

Narad:

\[\log _{3}3+\log _{3}x=\log _{3}(3x)=5\] \[3x=3^{5}=243\] x=243/3=81 Check \[\log _{3}3+\log _{3}81=\log _{3}243=\log _{3}3^{5}=5\] LHS=RHS

Nicole:

okay can you help me with a couple more pls?

Narad:

yes

Nicole:

http://prntscr.com/nmim3g

Narad:

True

Nicole:

http://prntscr.com/nmimfe

Narad:

2

Nicole:

http://prntscr.com/nmimwl

Narad:

-4.7

Nicole:

http://prntscr.com/nmin8c

Narad:

\[0.252^{x}=41\] \[xlog(0.252)=\log41\] \[x=\log41/\log0.252=-2.69\] Check \[0.252^{-2.69}=40.8\] LHS=RHS

Narad:

Option D

Nicole:

Got it http://prntscr.com/nminhp

Narad:

\[2lnx+2=1\] \[2lnx=2-1=1\] \[lnx=1/2\] \[x=e ^{1/2}\] x=1.65 This does not fit in the options

Nicole:

hmm

Narad:

I make the corrections \[lnx=-1/2\] \[x=e ^{-1/2}\] x=0.61 answer is option B

Nicole:

Got it http://prntscr.com/nmipbw

Narad:

\[x=\log _{3}15\] \[=\ln(15)/\ln(3)=2.46\] answer is option C

Nicole:

http://prntscr.com/nmnoyu

Nicole:

@Narad

Narad:

\[logx=\log(4x-9)\] \[x=4x-9\] \[3x=9\] x=3 Check \[\log(4*3-9)=\log3=logx\] RHS=LHS

Narad:

Answer is option A

Nicole:

okay http://prntscr.com/nmub6h

Nicole:

@Narad

Narad:

\[7*6^{3.05}=1653.7 \neq 64\] The answer is FALSE

Nicole:

okay http://prntscr.com/nmuozz these are right?^

Narad:

Nº2 correct nº3 correct nº4 correct

Nicole:

http://prntscr.com/nmutj4

Narad:

nº1 true nº2 if you write y=1/x as \[y=x ^{-1}\] you can sider y=1/x as an exponential function, TRUE

Narad:

nº2 no because it's not something to the power of x, it's FALSE

Nicole:

makes sense http://prntscr.com/nmuwri

Narad:

nº3 and nº4 are both TRUE

Nicole:

okay http://prntscr.com/nmuxfd

Narad:

nº12 \[y=Ae ^{bx}\] \[b <1\] No it's not an exponentila decay FALSE nº13 option C reflection in the x axis and a shift downwards by 2 units

Nicole:

Got it http://prntscr.com/nmuxyi

Narad:

nº16 the domain is \[\mathbb{R} \] option A nº17 option C \[y > 2\] nº18 Population is \[p=567(1+0.0015*9)=574\] if it's calculated like a simple interest otherwie, \[p=567(1+0.0015)^{9}=574\] it's the same answer

Nicole:

Got it http://prntscr.com/nmv2ic

Narad:

nº19 the population is \[P=100000*(1+0.045)^{5}=124618\] Nº18 there is a correction \[p=567*(1+0.015)^{9}= 648\]

Nicole:

okay got it http://prntscr.com/nmv4mr

Narad:

\[y=2^{x+1.6}\]

Nicole:

okay http://prntscr.com/nmv6od

Narad:

\[y=(1/2)^{x-1}\]

Nicole:

okay http://prntscr.com/nmv8ja

Narad:

\[f(x)=\log(x)\] \[g(x)=alog(x)\] The answer is option D

Nicole:

okay http://prntscr.com/nmva3x

Narad:

nº26 The domain is option B nº27 The range is all real numbers, option A nº28\[1.5^{3.8}=4.7\neq7\] The answer is FALSE nº29 \[x=\log _{2}100 = \ln100/\ln2=6.64\]

Nicole:

okay http://prntscr.com/nmvc5o

Narad:

option B

Nicole:

got it http://prntscr.com/nmvfol

Narad:

nº35 A horizontal shift by 3 units to the right and a vertical shift up by 5 units

Narad:

nº36 a horizontal shift by 3 units to the left and a vertical shift up by 2 uints

Nicole:

okay http://prntscr.com/nmvfu7

Narad:

nº37 3399 $ nº38 \[f(x)=logx\] \[g(x)=\log(x-h)\] The answer is option C nº39 The domain is x>-3

Nicole:

okay http://prntscr.com/nmvhxl

Narad:

nº40 \[2.4^{3.75}=26.7 \neq9\] The answer is FALSE nº41 \[3^{x+1}=500\] \[x+1=\log500/\log3=5.66\] x=5.66-1=4.66

Nicole:

okay thank you so much for the help

Narad:

You are welcome

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