Question

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Answer 1

@Vocaloid

Answer 2

In what quadrant is
\[\pi\]
radians

Answer 3

I think its 180

Answer 4

yes

Answer 5

okay

Convert 45° into radians.

Answer 6

\[180º = \pi rad\]

Answer 7

π/4?

Answer 8

yes

Answer 9

Convert 20° into radians.

Answer 10

π/9?

Answer 11

yes

Answer 12

Convert 930° into radians.

Answer 13

31π/6?

Answer 14

Yes

Answer 15

okay
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Answer 16

x is horizontal
y is vertical

Answer 17

how about questions 2 and 3?

Answer 18

Ratio of sides
\[x:y =1: \sqrt(3)\]

Answer 19

This is similar to a triangle with angles 90º, 60º and 30º

Answer 20

Okay got it and question 3?

Answer 21

The radius of the unit circle is = 1
x=1/2
\[y=\sqrt3/2\]

Answer 22

Okay makes sense

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Answer 23

This is incomplete

Answer 24

no its the question for the same triangle above

Answer 25

3rd quadrant
\[x=-1/2\] and
\[y=-\sqrt3/2\]

2nd quadrant
\[x=-1/2\] and
\[y=\sqrt3/2\]

4th quadrant
\[x= 1/2\] and
\[y=\sqrt3/2\]

Answer 26

4th quadrant
\[y=-\sqrt3/2\]

Answer 27

Okay

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Answer 28

Anticlockwise from O
\[(1,0)\]
\[(\sqrt3/2, 1/2)\]
\[(\sqrt2/2, \sqrt2/2)\]
\[(1/2, \sqrt3/2)\]
\[(0,1)\]
\[(-1/2, \sqrt3/2)\]
\[(-\sqrt2/2, \sqrt2/2)\]
\[(-\sqrt3/2, 1/2)\]
\[(-1,0)\]
\[(-\sqrt3/2, -1/2)\]
\[(-\sqrt2/2, \sqrt2/2)\]
\[(-1/2, -\sqrt3/2)\]
\[(0,-1)\]
\[(1/2,-\sqrt3/2)\]
\[(\sqrt2/2, -\sqrt2/2)\]
\[(\sqrt3/2, -1/2)\]

Answer 29

so I start from y?

Answer 30

no from x and going anticlockwise

Answer 31

The first number is the x-coordinate and the second number is the y-coordinate

Answer 32

but I would put the x and y coordinate in the same box?

Answer 33

yes as I have written them

Answer 34

separated by a comma

Answer 35

OKay got it thanks so much for the help

Answer 36

you are welcome